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# While person A walked 200m, person B walked 100m. They walked facing

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 8431
GMAT 1: 760 Q51 V42
GPA: 3.82
While person A walked 200m, person B walked 100m. They walked facing  [#permalink]

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06 Dec 2019, 01:34
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Difficulty:

15% (low)

Question Stats:

91% (01:52) correct 9% (01:41) wrong based on 23 sessions

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[GMAT math practice question]

While person $$A$$ walked $$200m$$, person $$B$$ walked $$100m$$. They walked facing each other for a distance of $$1500m$$ and met in $$10$$ minutes. Find the sum of the distances persons $$A$$ and $$B$$ walked in $$1$$ minute.

A. $$100m$$

B. $$120m$$

C. $$150m$$

D. $$160m$$

E. $$170m$$

_________________
MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy.
"Only $79 for 1 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" VP Status: Learning Joined: 20 Dec 2015 Posts: 1071 Location: India Concentration: Operations, Marketing GMAT 1: 670 Q48 V36 GRE 1: Q157 V157 GPA: 3.4 WE: Engineering (Manufacturing) Re: While person A walked 200m, person B walked 100m. They walked facing [#permalink] ### Show Tags 06 Dec 2019, 09:09 MathRevolution wrote: [GMAT math practice question] While person $$A$$ walked $$200m$$, person $$B$$ walked $$100m$$. They walked facing each other for a distance of $$1500m$$ and met in $$10$$ minutes. Find the sum of the distances persons $$A$$ and $$B$$ walked in $$1$$ minute. A. $$100m$$ B. $$120m$$ C. $$150m$$ D. $$160m$$ E. $$170m$$ It is a straight forward question we are given average velocity in terms of distance and time. Distance = 1500 m and time=10 minutes. When they both are travelling we have to add the distances covered by both. So the distance covered by A and B combined would be average velocity. So Average speed =1500/10 = 150 m/min So distance traveled A and B combined is 150 hence C is correct Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 8431 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: While person A walked 200m, person B walked 100m. They walked facing [#permalink] ### Show Tags 08 Dec 2019, 18:40 => Assume Va and Vb are the speeds of persons A and B, respectively. Then we have Va = 2Vb and 10Va + 10Vb = 10(2Vb) + 10Vb = 20Vb + 10Vb = 30Vb = 1500, and Vb = 50m/min. Then Va = 2Vb = 2(50) = 100m/min. Then the distances walked by persons A and B in 1 minute are 100m and 50m, respectively. So, the total distance = 100 + 50 = 150. Therefore, C is the answer. Answer: C _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 1 month Online Course"
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Re: While person A walked 200m, person B walked 100m. They walked facing   [#permalink] 08 Dec 2019, 18:40
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