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06 Dec 2019, 01:34
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C
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88% (01:52) correct
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[GMAT math practice question]
While person \(A\) walked \(200m\), person \(B\) walked \(100m\). They walked facing each other for a distance of \(1500m\) and met in \(10\) minutes. Find the sum of the distances persons \(A\) and \(B\) walked in \(1\) minute.
A. \(100m\)
B. \(120m\)
C. \(150m \)
D. \(160m\)
E. \(170m\)
While person \(A\) walked \(200m\), person \(B\) walked \(100m\). They walked facing each other for a distance of \(1500m\) and met in \(10\) minutes. Find the sum of the distances persons \(A\) and \(B\) walked in \(1\) minute.
A. \(100m\)
B. \(120m\)
C. \(150m \)
D. \(160m\)
E. \(170m\)
06 Dec 2019, 09:09
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MathRevolution
It is a straight forward question we are given average velocity in terms of distance and time.
Distance = 1500 m and time=10 minutes.
When they both are travelling we have to add the distances covered by both. So the distance covered by A and B combined would be average velocity.
So Average speed =1500/10 = 150 m/min
So distance traveled A and B combined is 150 hence C is correct
08 Dec 2019, 18:40
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Assume Va and Vb are the speeds of persons A and B, respectively.
Then we have Va = 2Vb and 10Va + 10Vb = 10(2Vb) + 10Vb = 20Vb + 10Vb = 30Vb = 1500, and Vb = 50m/min. Then Va = 2Vb = 2(50) = 100m/min.
Then the distances walked by persons A and B in 1 minute are 100m and 50m, respectively. So, the total distance = 100 + 50 = 150.
Therefore, C is the answer.
Answer: C
Assume Va and Vb are the speeds of persons A and B, respectively.
Then we have Va = 2Vb and 10Va + 10Vb = 10(2Vb) + 10Vb = 20Vb + 10Vb = 30Vb = 1500, and Vb = 50m/min. Then Va = 2Vb = 2(50) = 100m/min.
Then the distances walked by persons A and B in 1 minute are 100m and 50m, respectively. So, the total distance = 100 + 50 = 150.
Therefore, C is the answer.
Answer: C
