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While taking a certain standardized exam, Dave has 20 minutes to

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While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 07 Mar 2017, 23:56
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E

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  25% (medium)

Question Stats:

68% (01:12) correct 32% (01:10) wrong based on 140 sessions

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While taking a certain standardized exam, Dave has 20 minutes to finish his 600-word essay. Over the first 10 minutes, he averages 15 words per minute. By what percent must he increase his average words per minute to finish his essay in the remaining time?

A. 75%
B. 100%
C. 150%
D. 200%
E. 300%

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Re: While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 08 Mar 2017, 00:30
Words completed in the first 10 mins @15 words per min = 15*10 = 150 words
Remaining words to be completed = 600-150 =450
Rate for the remaining 10 mins = 450/10 = 45 words per min

Percent increase required = (45-15)*100/15 = 30*100/15 = 200%

Answer: D. 200%
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Re: While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 08 Mar 2017, 02:04
words written in 10 minutes = 15*10 = 150
words left = 600 -150 = 450
time left = 10 minutes
average should be 450/10 = 45 words/minute

% increase = {(45-15)/15} x100 = 200%

Option D
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Re: While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 08 Mar 2017, 13:09
1
D.

First 10 min
15*10=150

Second 10 min
Needs 450 words a min to catch up
450/10=45 a min needed

100% increase is 30 a min
200% increase is 45 a min
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Re: While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 10 Mar 2017, 10:43
1
Bunuel wrote:
While taking a certain standardized exam, Dave has 20 minutes to finish his 600-word essay. Over the first 10 minutes, he averages 15 words per minute. By what percent must he increase his average words per minute to finish his essay in the remaining time?

A. 75%
B. 100%
C. 150%
D. 200%
E. 300%


We are given that Dave needs to complete an essay in 20 minutes. Over the first 10 minutes, he averages 15 words per minute and thus competes 10 x 15 = 150 words, which means he has 600 - 150 = 450 words to complete in 10 minutes. That means he needs to average 450/10 = 45 words per minute in the last 10 minutes. We need to determine by what percentage his rate must increase to finish the essay on time. We can let x = the percentage increase and create the following equation to determine x:

15(1 + x/100) = 45

1 + x/100 = 3

x/100 = 2

x = 200

Answer: D
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Re: While taking a certain standardized exam, Dave has 20 minutes to  [#permalink]

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New post 27 Jul 2018, 10:06
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Re: While taking a certain standardized exam, Dave has 20 minutes to &nbs [#permalink] 27 Jul 2018, 10:06
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