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21 Jun 2024, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:48) correct
19%
(02:53)
wrong
based on 79
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Williams school has a total enrollment of 800 students. A mathematics fair was held at that school for three days recently. How many students among those enrolled in the school attended the fair on exactly two days?
(1) 10 percent of the students enrolled in the school did not attend the fair even on one day.
(2) Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
(1) 10 percent of the students enrolled in the school did not attend the fair even on one day.
(2) Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
21 Jun 2024, 02:07
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I think C,
Given - Williams school has a total enrollment of 800 students. A mathematics fair was held at that school for three days recently.
Assuming,
E1 = Number of students attended mathematics fair for exactly 1 day,
E2 = Number of students attended mathematics fair for exactly 2 days,
E3 = Number of students attended mathematics fair for exactly 3 days,
E' = Number of students did not attend fair
Therefore E1+E2+E3+E' = 800
1st - 10 percent of the students enrolled in the school did not attend the fair even on one day.
E' = 0.1*800 = 80
Nothing else. Hence Not sufficient.
2nd - Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
E1 = 0.8*800 = 640, E3 = 80. But nothing about E2, E'. Hence Not sufficient.
Combining both,
E1+E2+E3+E' = 800
640 + E2 + 80 + 80 = 800
E2=0.
Given - Williams school has a total enrollment of 800 students. A mathematics fair was held at that school for three days recently.
Assuming,
E1 = Number of students attended mathematics fair for exactly 1 day,
E2 = Number of students attended mathematics fair for exactly 2 days,
E3 = Number of students attended mathematics fair for exactly 3 days,
E' = Number of students did not attend fair
Therefore E1+E2+E3+E' = 800
1st - 10 percent of the students enrolled in the school did not attend the fair even on one day.
E' = 0.1*800 = 80
Nothing else. Hence Not sufficient.
2nd - Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
E1 = 0.8*800 = 640, E3 = 80. But nothing about E2, E'. Hence Not sufficient.
Combining both,
E1+E2+E3+E' = 800
640 + E2 + 80 + 80 = 800
E2=0.
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21 Jun 2024, 06:00
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Williams school has a total enrollment of 800 students. A mathematics fair was held at that school for three days recently. How many students among those enrolled in the school attended the fair on exactly two days?
(1) 10 percent of the students enrolled in the school did not attend the fair even on one day.
(2) Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
Solution
Given : Total enrollment of students = 800
Fair was held for three days
To find : No. of students attended fair on exactly two days
Statement 1 Insufficient
10 percent of the students enrolled in the school did not attend the fair even on one day.
800 * 10/100 = 80 students did not attend the fair even on one day
Statement 2 Insufficient
Of the students enrolled, 80 percent attended the fair on exactly one of the three days and 80 participated at the fair on all three days.
80% of 800 = 640 ( attended the fair for exactly one of the three days)
Students attended the fair on all three days = 80
When we combine both statements we get the conclusive answer
Total students = 1 day + 2 days + 3 days + Neither
800 = 640 + x day + 80 + 80= 800-800 = 0 day
Hence, Option C
(1) 10 percent of the students enrolled in the school did not attend the fair even on one day.
(2) Of the students enrolled in the school, 80 percent attended the fair on exactly one of the three days and 80 attended the fair on all the three days.
Solution
Given : Total enrollment of students = 800
Fair was held for three days
To find : No. of students attended fair on exactly two days
Statement 1 Insufficient
10 percent of the students enrolled in the school did not attend the fair even on one day.
800 * 10/100 = 80 students did not attend the fair even on one day
Statement 2 Insufficient
Of the students enrolled, 80 percent attended the fair on exactly one of the three days and 80 participated at the fair on all three days.
80% of 800 = 640 ( attended the fair for exactly one of the three days)
Students attended the fair on all three days = 80
When we combine both statements we get the conclusive answer
Total students = 1 day + 2 days + 3 days + Neither
800 = 640 + x day + 80 + 80= 800-800 = 0 day
Hence, Option C
