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# WORK DONE

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Senior Manager
Joined: 02 Dec 2007
Posts: 448

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02 Aug 2009, 07:26
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TO DO A CERTAIN WORK, B WOULD TAKE 3 TIMES AS LONG AS A AND C TOGETHER AND C TWICE AS LONG AS A AND B TOGETHER.THE THREE MEN TOGETHER COMPLETE THE WORK IN 10 DAYS. HOW LONG WOULD EACH TAKE SEPARATELY?

[Reveal] Spoiler:
A,B,C --24, 40 AND 30 DAYS RESPECTIVELY
Manager
Joined: 10 Jul 2009
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02 Aug 2009, 08:30
Let a,b and c be the units of work done by A, B and C respectively.

B WOULD TAKE 3 TIMES AS LONG AS A AND C TOGETHER => 3b = a+ c
C TWICE AS LONG AS A AND B TOGETHER => 2c = a +b
b = (a+c)/3
Substituting in the 2 equation we get
2c = a + (a+c)/3
6c = 3a + a + c
5c = 4a
a/c = 5/4
a:b:c = 5:3:4
Since all three can complete the work in 10 days
Total number of unit of wrk = (5+3+4)10 = 120

Number of days taken by A to complete the work = 120/5 = 24 days
Number of days taken by B to complete the work = 120/3 = 40 days
Number of days taken by A to complete the work = 120/4 = 30 days
Re: WORK DONE   [#permalink] 02 Aug 2009, 08:30
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# WORK DONE

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