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mand-y
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mand-y
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Pipe A can fill a pool in 6 hrs
Hence Pipe A can fill in 2 hrs 1/3 of the pool.

Remaining pool to be filled = 2/3

Pipe A can fill a pool in 6 hrs
Hence Pipe A can fill 2/3 of pool in 6*2/3 = 4 hrs

Pipe B can fill the pool in 6 hrs
Hence Pipe B cab fill 2/3 of the pool in 6*2/3 = 4 hrs

Let time taken by both the pipes be X
Hence,

1/X = 1/4 + 1/4 = 2/4 =1/2

Hence 2 hrs ,

Hence after the second pipe is opened they both can fill the pool in 2 hrs.
Total time taken = 4
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As the two pipes fill the pool at the same rate, we can say that 6 pipe-hours are needed to fill the pool.

If pipe A is left open for 2 hours before pipe B opens, the pipes will have filled the pool after 6-2=4 pipe-hours (i.e the two pipes open for two hours).

Answer:2 hours
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If the first pipe is open for 2 hours the pool will be filled 1/6*2=1/3 of its capacity
so 2/3 of the work left the work rate of two pipes combined is (1/6)*2=1/3
(2/3)/(1/3)=2
my answer is 2 hours



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