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# Working at their respective constant rates, printing machine X, Y, and

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Manager
Joined: 10 Feb 2011
Posts: 107
Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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Updated on: 24 Apr 2015, 08:31
1
11
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Difficulty:

25% (medium)

Question Stats:

77% (01:40) correct 23% (02:13) wrong based on 257 sessions

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Working at their respective constant rates, printing machine X, Y, and Z can finish a certain work in 9, 12, and 18 hours. If three machines work together to finish the work, what fraction of the work will be finished by the machine Z?

(A) 4/9
(B) 1/3
(C) 1/4
(D) 2/9
(E) 1/9

Originally posted by banksy on 17 Feb 2011, 15:11.
Last edited by Bunuel on 24 Apr 2015, 08:31, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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Re: Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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17 Feb 2011, 19:47
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2
banksy wrote:
192. Working at their respective constant rates, printing machine X, Y, and Z can finish a certain work in 9, 12, and 18 hours. If three machines work together to finish the work, what fraction of the work will be finished by the machine Z?
(A)
(B)
(C)
(D)
(E)

Since time taken by X, Y and Z is in the ratio 9:12:18 i.e. 3:4:6,
their speeds are in the ratio $$\frac{1}{3}:\frac{1}{4}:\frac{1}{6} = 4:3:2$$
So Z will do $$\frac{2}{(4+3+2)} = 2/9$$ of the work
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Re: Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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18 Feb 2011, 01:48
7
X; 9 hour-> 1 work
=> 1 hour -> 1/9 work

Y; 12 hour-> 1 work
=> 1 hour-> 1/12 work

Z; 18 hour-> 1 work
=> 1 hour-> 1/18 work

Total work done by all machines in 1 hour;
1/9+1/12+1/18 = (4+3+2)/36=9/36=1/4 work

Jointly;
1/4 work-> 1 hour
1 work-> 1/(1/4) = 4 hours(Jointly X,Y,Z all spent for 4 hours towards completing the job)

We know from before;
Z; 18 hour-> 1 work
=> 1 hour-> 1/18 work

If Z can perform 1/18 work in 1 hour;
In 4 hours, he would have performed
(1/18)*4 work
2/9 work

Ans: 2/9
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Joined: 02 Sep 2009
Posts: 55681
Re: Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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17 Feb 2011, 16:02
2
2
banksy wrote:
192. Working at their respective constant rates, printing machine X, Y, and Z can finish a certain work in 9, 12, and 18 hours. If three machines work together to finish the work, what fraction of the work will be finished by the machine Z?
(A)
(B)
(C)
(D)
(E)

In 1 hour X can finish 1/9=4/36 of the work, Y can finish 1/12=3/36 of the work and Z can finish 1/18=2/36 of the work. So in 1 hour out of 4+3+2=9 parts of the work Z finished 2 parts or 2/9 of the work.

Or if Z can do 1 part in some time interval then in the same time interval X can do 2 parts (as its rate is twice the rate of Z), and Y can do 1.5 parts (again as its rate is 1.5 times the rate of Z) so share of Z is 1 out of 1+2+1.5=4.5, or 1/4.5=2/9.

Please provide the answer choices for PS questions.
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GPA: 3.25
Re: Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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03 May 2016, 13:59
The fraction of the work performed by Z is :

Rz / (Rx + Ry + Rz) = (1/18) / (1/9 + 1/12 + 1/18) = (1/18)/(1/4) = 2/9
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Posts: 11396
Re: Working at their respective constant rates, printing machine X, Y, and  [#permalink]

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29 Nov 2018, 09:22
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Re: Working at their respective constant rates, printing machine X, Y, and   [#permalink] 29 Nov 2018, 09:22
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