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22 Jul 2007, 13:16
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A group of 4 pumps are filling a tank. Each of the 3 smaller pumps works at 2/3rds the rate of the largest pump. If all 4 pumps work at the same time, they should fill the tank in what fraction of the time that it would taken the largest pump if it operated alone?
A) 4/7
B) 1/3
C) 2/3
D) 3/4
E) 4/3
I don't know how to approach this problem, thanks.
A) 4/7
B) 1/3
C) 2/3
D) 3/4
E) 4/3
I don't know how to approach this problem, thanks.
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22 Jul 2007, 13:31
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I get B.
Let R be the rate of the largest pump.
Then, rate of 3 smaller pumps is (2/3)*R.
If all 4 pumps working together, then combined rate is (R+3*(2/3)*R) 3R.
Time taken by 4 pumps is 1/(3R).
Had largest pump operated alone, it would have taken 1/R time.
We want to find [1/(3R)]/1/R = 1/3.
Please post OA.
Thanks.
Let R be the rate of the largest pump.
Then, rate of 3 smaller pumps is (2/3)*R.
If all 4 pumps working together, then combined rate is (R+3*(2/3)*R) 3R.
Time taken by 4 pumps is 1/(3R).
Had largest pump operated alone, it would have taken 1/R time.
We want to find [1/(3R)]/1/R = 1/3.
Please post OA.
Thanks.
22 Jul 2007, 13:34
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Let the large tank's rate be x. Then the four machine's combined rate is x+(2/3)x+(2/3)x+(2/3)x=3x. So together they work 3 times as fast, so it will take 1/3 the time.
B
B
