Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:49) correct
12%
(01:11)
wrong
based on 220
sessions
History
Date
Time
Result
Not Attempted Yet
07 Mar 2020, 12:22
Kudos
Bookmarks
Emma2511
|x - 2| = 2|x - 2|. Solve for x.
A. -2
B. 0
C. 2
D. 4
E. 6
A. -2
B. 0
C. 2
D. 4
E. 6
|x - 2| = 2|x - 2|;
0 = 2|x - 2| - |x - 2|;
0 = |x - 2|;
x = 2.
Answer: C.
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 09 Dec 2024
Posts: 3,116
Own Kudos:
Given Kudos: 1,510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
07 Mar 2020, 12:51
Kudos
Bookmarks
Emma2511
|x - 2| = 2|x - 2|. Solve for x.
A. -2
B. 0
C. 2
D. 4
E. 6
A. -2
B. 0
C. 2
D. 4
E. 6
Since we know module could be solved as either positive or negative value.
Case 1: |X-2|=2|X-2|
X-2 = 2(x-2) Both positive
X=2
Case 2: |X-2|=2|X-2|
X-2 = 2*-(x-2) L.H.S positive, R.H.S. negative
X=2
Case 3: |X-2|=2|X-2|
-(X-2) = 2*-(x-2) Both negative
X=2
Case 4: |X-2|=2|X-2|
-(X-2) = 2*(x-2) L.H.S negative, R.H.S. positive
X=2
So no matter what. X value is coming down to 2.
So OA is C
Posted from my mobile device
