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12 Sep 2025, 10:22
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
16% (00:19) correct
83% (00:49) wrong based on 6 sessions
History
Date
Time
Result
Not Attempted Yet
27 Sep 2025, 12:25
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Official Explanation
Many equations with an \(x^2\) are solved by first getting one side equal to 0. If \(x^2 + 5x = 6\) then \(x^2 +5x – 6 = 0. \)The left side is factored as \((x + 6)(x – 1),\) since \(6x – 1x = 5x\). Quantity (A) exactly matches the factored form \((x + 6)(x – 1),\) which equals 0. Since \(1 > 0,\) Quantity (B) is greater.
Answer: B
Many equations with an \(x^2\) are solved by first getting one side equal to 0. If \(x^2 + 5x = 6\) then \(x^2 +5x – 6 = 0. \)The left side is factored as \((x + 6)(x – 1),\) since \(6x – 1x = 5x\). Quantity (A) exactly matches the factored form \((x + 6)(x – 1),\) which equals 0. Since \(1 > 0,\) Quantity (B) is greater.
Answer: B
