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Sajjad1994
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Solution is not clear. how can we compare 4 with 1/2^-x? we just have given rel between x and y and on simplyfying B weger 2^x now 4 and 2^x how can we compare? If y>0 so if y=1 then x=2*1 = 2 then B = 2^2 so A=B but if y=2 then x=2*2=4 then 2^4>4. Which means relation is not clear. Answer should be D

Quantity A can be written as
[ltr](2^2)y=2^2y = 4.[/ltr]

you have written this so you are assuming y = 1?
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Explanation

Quantity 1: 4

Quantity 2: \(\frac{1}{2^{-x}}=2^x.\)

Since \(x=2y:\)

\(2^x=2^{2y}=4^y.\)

So Quantity 2 is \(4^y.\)

Comparison:

Quantity 1: 4
Quantity 2: \(4^y\) with y a positive integer.

If \(y=1,\) Quantity \(2 = 4^1=4\) ----> equal.

[*]If \(y>1,\) Quantity \(2 >4.\)

Since \(y\) is a positive integer, \(y≥1.\)

Answer: D
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At Quantity 2: 1/(2^-x) = 2^x (not 2x)
Sajjad1994
Explanation

Quantity 1: 4

Quantity 2: \(\frac{1}{2^{-x}}=2x.\)

Since \(x=2y:\)

\(2^x=2^{2y}=4^y.\)

So Quantity 2 is \(4^y.\)

Comparison:

Quantity 1: 4
Quantity 2: \(4^y\) with y a positive integer.

If \(y=1,\) Quantity \(2 = 4^1=4\) ----> equal.

[*]If \(y>1,\) Quantity \(2 >4.\)

Since \(y\) is a positive integer, \(y≥1.\)

Answer: D