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# (X^3)*(Y^4)=5000. Find Y. (1) X and Y are integers (2) Y>0

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(X^3)*(Y^4)=5000. Find Y. (1) X and Y are integers (2) Y>0 [#permalink]

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20 Jul 2003, 01:00
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(X^3)*(Y^4)=5000. Find Y.

(1) X and Y are integers
(2) Y>0
GMAT Instructor
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Schools: Haas, MFE; Anderson, MBA; USC, MSEE
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20 Jul 2003, 06:41
Brainless wrote:
A

Be careful. Y is raised to an even power.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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20 Jul 2003, 06:51
Expressing 5000 as product of primes , we get
5000 = 2^3 x 5^4

==> x = 3 and y = 4 . (1) says both x and y are integers.

Am I missing something ?
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Brainless

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20 Jul 2003, 07:46
2^3 * 5^4 = 5000
2^3 *-5^4 = 5000

are both the same here. You need (2) to find the only solution. Thus, it is C.

Be careful with even powers!
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20 Jul 2003, 09:25
thanks so much for these problems, they're great!
20 Jul 2003, 09:25
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