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# x – 3[2 – (3 – x)] =

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Re: x – 3[2 – (3 – x)] = [#permalink]
=> X-3(2-(3-x)
=> X-3(2-3+x)
=> X-3(-1+x)
=> X+3-3x
=> 3-2x

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Re: x – 3[2 – (3 – x)] = [#permalink]
its B

X-3[2-3-X]
X-3[X-1]
X-3X+3
3-2X

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Re: x – 3[2 – (3 – x)] = [#permalink]
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Bunuel
x – 3[2 – (3 – x)] =

A. 3
B. 3 – 2x
C. 6 – 2x
D. 3 + 3x
E. 3 – 3x

PS21248

Take: x – 3[2 – (3 – x)]
Simplify the red part to get: x – 3[(–1) + x]
Take: x – 3[(–1) + x]
Expand to get: x + 3 – 3x
Simplify: 3 - 2x

Cheers,
Brent
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Re: x – 3[2 – (3 – x)] = [#permalink]
Bunuel
Batman117
I think there is typo in question.

Posted from my mobile device
________________________
Just checked. No typo there.
I just consider (x-3) instead of x-3() ?
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Re: x – 3[2 – (3 – x)] = [#permalink]
Bunuel
x – 3[2 – (3 – x)] =

A. 3
B. 3 – 2x
C. 6 – 2x
D. 3 + 3x
E. 3 – 3x

PS21248
$$x – 3[2 – (3 – x)]$$

$$= x – 3[2 – 3 + x]$$

$$= x – 3[-1 + x]$$

$$= x + 3 - 3x]$$

$$= 3 - 2x]$$, Answer must be (B)
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Re: x 3[2 (3 x)] = [#permalink]
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Re: x 3[2 (3 x)] = [#permalink]
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