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17 Jan 2019, 22:10
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
58% (00:58) correct
42%
(01:00)
wrong
based on 142
sessions
History
Date
Time
Result
Not Attempted Yet
X and Y are distinct non negative real numbers. What is the sum (X+Y)?
(1) (X^2 - Y^2)/(X-Y) = 6
(2) (X+Y)^2 = 36
(1) (X^2 - Y^2)/(X-Y) = 6
(2) (X+Y)^2 = 36
17 Jan 2019, 22:20
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From statement 1:
\(\frac{x^2-y^2}{x-y} = 6\)
\(\frac{(x+y)(x-y)}{x-y} = 6\)
\(x+y = 6\)
Sufficient.
From statement 2:
\((x+y)^2 = 36\)
x+y = +6 or -6
Insufficient.
A is the answer.
\(\frac{x^2-y^2}{x-y} = 6\)
\(\frac{(x+y)(x-y)}{x-y} = 6\)
\(x+y = 6\)
Sufficient.
From statement 2:
\((x+y)^2 = 36\)
x+y = +6 or -6
Insufficient.
A is the answer.
17 Jan 2019, 23:41
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Afc0892
Answer should be D if you account for the fact that x and y are non negative, therefore x+y=-6 is not a viable option.
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