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Basshead
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x^n = x^(n+2) for any integer n. Is it true that x > 0? 30 Oct 2021, 13:42
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aa008
I do not know why no body has solved in this way-

\(x^n\)=\(x^{(n+2)}\)
\(x^n\)=\(x^n\)*\(x^2\)

so
\(x^2\)=1
x=-1 or +1

Statement 1: sufficient
put -1 and +1 in the expression
only -1 satisfy the equation
so x=-1

Statement 1: sufficient
put -1 and +1 in the expression
only -1 satisfy the equation
so x=-1

so both the statements gives the solution hence answer is D
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This reasoning is not correct.

While you arrived at the correct answer, it was by luck. When you divided by \(x^n\), you eliminated 0 as a solution.
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x^n = x^(n+2) for any integer n. Is it true that x > 0? 02 Nov 2025, 21:19
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