|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
01 May 2025, 09:49
Kudos
Bookmarks
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
33% (01:23) correct
66% (00:35) wrong based on 3 sessions
History
Date
Time
Result
Not Attempted Yet
05 May 2025, 19:37
Kudos
Bookmarks
x + y = 5 ...(1)
y – x = –5 ...(2)
(1) + (2)
=> x + y + y - x = 5 + (-5)
=> 2y = 5 - 5 = 0
=> y = 0
Clearly, Quantity A(y) = Quantity B(0)
So, Answer will be C
Hope it helps!
y – x = –5 ...(2)
(1) + (2)
=> x + y + y - x = 5 + (-5)
=> 2y = 5 - 5 = 0
=> y = 0
Clearly, Quantity A(y) = Quantity B(0)
So, Answer will be C
Hope it helps!
18 May 2025, 00:15
Kudos
Bookmarks
OE
Add the equations.
x+y=5
+y-x=-5
2y=0
Since 2y = 0, y = 0.
Could y = 0? In each equation, if y = 0, then x = –5. So, y can equal 0. Eliminate Choices A and B, and either guess between Choices C and D or continue. Must y = 0? Yes, when you have two linear equations in two variables, there is only one solution, so nothing else is possible.
Answer: C
Add the equations.
x+y=5
+y-x=-5
2y=0
Since 2y = 0, y = 0.
Could y = 0? In each equation, if y = 0, then x = –5. So, y can equal 0. Eliminate Choices A and B, and either guess between Choices C and D or continue. Must y = 0? Yes, when you have two linear equations in two variables, there is only one solution, so nothing else is possible.
Answer: C
