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03 Nov 2007, 17:52
Kudos
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x, y and z are three digits numbers, and x=y+z. Is the hundreds’ digit of x equal to the sum of hundreds’ digits of y and z?
1). the tens’ digit of x equal to the sum of tens’ digits of y and z
2). the units’ digit of x equal to the sum of units’ digits of y and z
1). the tens’ digit of x equal to the sum of tens’ digits of y and z
2). the units’ digit of x equal to the sum of units’ digits of y and z
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03 Nov 2007, 20:33
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Ravshonbek
Using 1) we know ten's digit of either y or z is <=5 and other has to be <=4
if there is carry over from units digt we may be in toruble baecause tents digit of 5+4 and carry over will carry over to hundred's digit
Insufficnet
Using 2) We know there is no cary over to tens place dont say anyting about 100th place
insufficnet
Togather we know there is no carry forward from unit palce and no carry forward from 10n place
so 100 didgit wil be sum of y and zth 100 digit
Sufficnet
Answer C
04 Nov 2007, 12:41
Kudos
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I will go with A.
From statement 1 we can say that there is no carry over from the ten's digit to the hundred's digit. So the hundreds' digit of x will be sum of the hundreds' digit of y & z.
Sufficient
From 2 we can say that there is no carry over to the tens' digit but we can not say that there is no carry over from the tens' digit to the hundreds' digit. So condition 2 is not suff
From statement 1 we can say that there is no carry over from the ten's digit to the hundred's digit. So the hundreds' digit of x will be sum of the hundreds' digit of y & z.
Sufficient
From 2 we can say that there is no carry over to the tens' digit but we can not say that there is no carry over from the tens' digit to the hundreds' digit. So condition 2 is not suff
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
