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15 Oct 2020, 08:46
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:23) correct
35%
(01:02)
wrong
based on 97
sessions
History
Date
Time
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Not Attempted Yet
If x and y are positive integers, 80 = 22x + y what is the value of y?
(1) x = 3
(2) y < 22
(1) x = 3
(2) y < 22
15 Oct 2020, 09:18
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Quote:
Step 1: Understanding statement 1 alone
(1) x = 3
y = 14
Sufficient
Step 2: Understanding statement 2 alone
(2) y < 22
22x + y = 80
y = 80 - 22x
When x = 1; y = 58, not possible
When x = 2; y = 36, not possible
When x = 3; y = 14, possible
When x = 4; y = -8, not possible
Only y = 14 is possible
Sufficient
IMO D
15 Oct 2020, 09:28
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Explanation:
Given: x and y are positive integers,
80 = 22x + y --- Eqn 1
To find = what is the value of y?
Statement 1: x = 3
Putiing value of x in eqn 1
80 = 22x3 + y
y = 80-66
y = 14
Sufficient
Statement 2: y < 22
If x is 1, then y = 58
x is 2, then y = 36
x is 3, then y = 14
x is 4, then y = -8 (-ve)
So only value which is possible is 14
Sufficient
IMO-D
Given: x and y are positive integers,
80 = 22x + y --- Eqn 1
To find = what is the value of y?
Statement 1: x = 3
Putiing value of x in eqn 1
80 = 22x3 + y
y = 80-66
y = 14
Sufficient
Statement 2: y < 22
If x is 1, then y = 58
x is 2, then y = 36
x is 3, then y = 14
x is 4, then y = -8 (-ve)
So only value which is possible is 14
Sufficient
IMO-D
