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# XY Coordinate Question

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Intern
Joined: 16 Sep 2006
Posts: 22
XY Coordinate Question  [#permalink]

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22 Sep 2006, 11:07
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:20) correct 0% (00:00) wrong based on 6 sessions

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I don't even know how to approach this. Any help would be appreciated. Thanks

In the XY- Coordinate system, if (a,b) and (a+3, b+k) are two points on the line defined by the equation x=3y-7, then k =

A. 9
B. 3
C. 7/3
D. 1
E. 1/3

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SVP
Joined: 01 May 2006
Posts: 1786

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22 Sep 2006, 11:15
(D)

Since the 2 points are on the line represented by x=3y-7, thus X and Y of each point must verify the equation.

So,
(1) a = 3*b - 7
(2) a+3 = 3*(b+k) - 7

(2) - (1) <=> 3 = 3*k
<=> k = 1
VP
Joined: 02 Jun 2006
Posts: 1233

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22 Sep 2006, 11:28
D. 1

Eqn of the line : x-3y = -7

As (a, b) on the line:
a-3b = -7

As (a+3, b+k) on the line:

a+3 -3(b+k) = -7

or a + 3 - 3b -3k = -7

or (a-3b) + 3(1-k) = -7

or -7 + 3(1-k) = -7 as (a-3b) = -7 Frm (1)

or 3(1-k) = 0

Or 1 = k..

Manager
Joined: 30 Mar 2007
Posts: 205

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16 May 2007, 04:46
slop = k/3

x=3y-7 =>y=1/3x+7/3

k/3=1/3

k=1
Intern
Joined: 10 Jun 2009
Posts: 29
Location: Stockholm, Sweden
Re: XY Coordinate Question  [#permalink]

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16 Jun 2009, 00:39
Just plug in 3 into the formula. No need to make any equations really. The intercept is irrelevant so the only thing you have to take into account is x = 3y (a = 3b)

3 = 3b
1 = b

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: XY Coordinate Question &nbs [#permalink] 16 Jun 2009, 00:39
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# XY Coordinate Question

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