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XY Coordinate Question

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Intern
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Joined: 16 Sep 2006
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XY Coordinate Question [#permalink]

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New post 22 Sep 2006, 11:07
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A
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D
E

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I don't even know how to approach this. Any help would be appreciated. Thanks

In the XY- Coordinate system, if (a,b) and (a+3, b+k) are two points on the line defined by the equation x=3y-7, then k =

A. 9
B. 3
C. 7/3
D. 1
E. 1/3

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SVP
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 [#permalink]

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New post 22 Sep 2006, 11:15
(D)

Since the 2 points are on the line represented by x=3y-7, thus X and Y of each point must verify the equation.

So,
(1) a = 3*b - 7
(2) a+3 = 3*(b+k) - 7

(2) - (1) <=> 3 = 3*k
<=> k = 1

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VP
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New post 22 Sep 2006, 11:28
D. 1

Eqn of the line : x-3y = -7

As (a, b) on the line:
a-3b = -7

As (a+3, b+k) on the line:

a+3 -3(b+k) = -7

or a + 3 - 3b -3k = -7

or (a-3b) + 3(1-k) = -7

or -7 + 3(1-k) = -7 as (a-3b) = -7 Frm (1)

or 3(1-k) = 0

Or 1 = k..

Answer:D

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Manager
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New post 16 May 2007, 04:46
slop = k/3

x=3y-7 =>y=1/3x+7/3

k/3=1/3

k=1

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Intern
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Re: XY Coordinate Question [#permalink]

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New post 16 Jun 2009, 00:39
Just plug in 3 into the formula. No need to make any equations really. The intercept is irrelevant so the only thing you have to take into account is x = 3y (a = 3b)

3 = 3b
1 = b

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Re: XY Coordinate Question   [#permalink] 16 Jun 2009, 00:39
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