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18 Dec 2018, 23:19
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Using (a,b) in the equation of line,
a = 3b – 7 eq(1)
Now, using (a+3, b+k) in the equation of line,
a+3 =3(b+k) – 7 eq(2)
Using eq(1) in eq (2), we get
K = 1.
Hence, d is the answer.
a = 3b – 7 eq(1)
Now, using (a+3, b+k) in the equation of line,
a+3 =3(b+k) – 7 eq(2)
Using eq(1) in eq (2), we get
K = 1.
Hence, d is the answer.
27 Sep 2019, 11:42
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If we transform x = 3y-7 to be y = (1/3)x+7/3 we can see the slope is 1/3
Since we're asked for a+3, this is one "run" of the slope (3)
Then k has to be 1, since the "rise" is 1.
Another way is plug in and to subtract the 2nd point from the first:
(a+3) = 3(b+k) - 7
a = 3b - 7
-__________
3 = 3k
1 = k
Since we're asked for a+3, this is one "run" of the slope (3)
Then k has to be 1, since the "rise" is 1.
Another way is plug in and to subtract the 2nd point from the first:
(a+3) = 3(b+k) - 7
a = 3b - 7
-__________
3 = 3k
1 = k
01 Feb 2023, 05:39
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This question can be solved by plugging in the two ordered pairs into the slope formula.
While this equation may seem unsolvable upon glance because of the multiple variables, a and b cancel out and we're left left with k.
While this equation may seem unsolvable upon glance because of the multiple variables, a and b cancel out and we're left left with k.
