Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 21 Jul 2009
Posts: 226
Location: New York, NY

Yesterday each of the 35 members of a certain task force
[#permalink]
Show Tags
21 Oct 2009, 08:56
Question Stats:
56% (01:14) correct 44% (01:11) wrong based on 558 sessions
HideShow timer Statistics
Attachment:
13996medium.jpg [ 11.87 KiB  Viewed 12334 times ]
Yesterday each of the 35 members of a certain task force spent some time working on project P. The graph shows the number of hours and the number of members who spent that number of hours working on project P yesterday. What was the median number of hours that the members of the task force spent working on project P yesterday? A. 2 B. 3 C. 4 D. 5 E. 6
Official Answer and Stats are available only to registered users. Register/ Login.



Math Expert
Joined: 02 Sep 2009
Posts: 47188

Re: 35 members of a certain task force
[#permalink]
Show Tags
21 Oct 2009, 10:12
mendelay wrote: Attachment: 13996medium.jpg Yesterday each of the 35 members of a certain task force spent some time working on project P. The graph shows the number of hours and the number of members who spent that number of hours working on project P yesterday. What was the median number of hours that the members of the task force spent working on project P yesterday? A. 2 B. 3 C. 4 D. 5 E. 6 We have set consisting of 35 terms (terms=number of members): 9+4+1+2+1+8+10=35. Median of a set, with odd number of terms, would be the middle term, so 18th term. Values of terms: 9 terms=1, 4 terms=2, 1 term=3, 2 terms=4 , 1 term=5, 8 terms=6 and 10 terms=7 > 18th term is 6. To illustrate: 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 4, 4, 5, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7. Answer: E.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Manager
Joined: 16 Feb 2010
Posts: 189

Re: 35 members of a certain task force
[#permalink]
Show Tags
30 Aug 2010, 16:53
IMO E as always, went the long way
1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 4, 4, 5, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7.



Math Expert
Joined: 02 Sep 2009
Posts: 47188

Re: Yesterday each of the 35 members of a certain task force
[#permalink]
Show Tags
18 Jun 2013, 01:40



Intern
Joined: 28 Apr 2013
Posts: 16
GMAT Date: 08032013
GPA: 3.3
WE: Supply Chain Management (Military & Defense)

Re: Yesterday each of the 35 members of a certain task force
[#permalink]
Show Tags
21 Sep 2013, 15:49
A little unorthodox approach, but so far it has worked for these types of problems. I set up the number of people that worked that many hours in a number line:
9  4  1  2  1  8  10
As Bunuel said we have 35 terms so the middle, 18th term, will be the median.
I then start crossing off from either end until I find the "1" remaining:
9 4 1 2 1 8 10 0 4 1 2 1 8 1 0 3 1 2 1 8 0 0 0 1 2 1 5 0 0 0 0 2 1 4 0 0 0 0 0 1 2 0 0 0 0 0 0 1 0  Therefore it's the sixth term, in this case "6 hours"....hope it makes sense, just a minor shortcut over writing out all 35 terms.



GMAT Club Legend
Joined: 16 Oct 2010
Posts: 8132
Location: Pune, India

Re: Yesterday each of the 35 members of a certain task force
[#permalink]
Show Tags
27 Nov 2014, 21:27
Nwsmith11 wrote: A little unorthodox approach, but so far it has worked for these types of problems. I set up the number of people that worked that many hours in a number line:
9  4  1  2  1  8  10
As Bunuel said we have 35 terms so the middle, 18th term, will be the median.
I then start crossing off from either end until I find the "1" remaining:
9 4 1 2 1 8 10 0 4 1 2 1 8 1 0 3 1 2 1 8 0 0 0 1 2 1 5 0 0 0 0 2 1 4 0 0 0 0 0 1 2 0 0 0 0 0 0 1 0  Therefore it's the sixth term, in this case "6 hours"....hope it makes sense, just a minor shortcut over writing out all 35 terms. Or, just start adding the number of members till you reach 18 (since you are already given in the question that there are 35 members who worked) 9+4+1+2+1 = 17 So the next fellow who worked for 6 hrs is the 18th member and lies at the median i.e. median is 6. Answer (E)
_________________
Karishma Private Tutor for GMAT Contact: bansal.karishma@gmail.com



NonHuman User
Joined: 09 Sep 2013
Posts: 7332

Re: Yesterday each of the 35 members of a certain task force
[#permalink]
Show Tags
28 Aug 2017, 10:21
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources




Re: Yesterday each of the 35 members of a certain task force &nbs
[#permalink]
28 Aug 2017, 10:21






