Bunuel
Yesterday it took a certain plane 3 hours to fly from City A to City B at an average speed of 400 miles per hour. Today the same plane flew from City A to City B along the same route at an average speed of 450 miles per hour. How many more minutes took the plane to fly yesterday than it took today?
A. 10
B. 15
C. 20
D. 25
E. 30
"it took a certain plane 3 hours to fly from City A to City B at an average speed of 400 miles per hour."
We should immediately deduct the total distance is \(400 mi/h * 3 h = 1200 mi\) upon seeing this. Then the 2nd trip took \(\frac{{1200 mi}}{{450 mi/h}} = 2 + \frac{300}{450} = 2 + \frac{2}{3} = 2 hours 40 min\). Therefore he saved 20 min by driving 50 mi/h faster.
Another interesting way to approach this is to use the ratio method, the distance is fixed so the time and speed have an inverse proportional relation. The speed is multiplied by \(9/8\) in order to go from 400 to 450. Then the time is multiplied by \(\frac{8}{9}\), so \(\frac{1}{9}\) less and \(\frac{1}{9}\) of 3 hours is 20 min.
Ans: C