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14 Sep 2005, 16:58
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You are in a roomful of 35 people. Everyone is asked to shake hands with everyone. How many handshakes will there be?
i found many formulas to compute . the number of handshakes such as :
n2-n/2. OR n(n-1)/2
plz explains your works
thanks
i found many formulas to compute . the number of handshakes such as :
n2-n/2. OR n(n-1)/2
plz explains your works
thanks
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14 Sep 2005, 17:18
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Considering that:
A shaking hand with B is diffrent than:
B shaking hand with A
we have 35P2 permutations (order matter as per premise).
35 P 2 = 35! / (35 - 2) ! = 35 * 34 * 33!/33! = 35 * 34 = 1190
A shaking hand with B is diffrent than:
B shaking hand with A
we have 35P2 permutations (order matter as per premise).
35 P 2 = 35! / (35 - 2) ! = 35 * 34 * 33!/33! = 35 * 34 = 1190
14 Sep 2005, 18:43
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I think it should be 35C2 => or 1190/2 = 595.
This needs to be treated similar to problems involving X number of teams playing where 2 teams play each other (once only), hence total number of games played is XC2. Is that correct?
This needs to be treated similar to problems involving X number of teams playing where 2 teams play each other (once only), hence total number of games played is XC2. Is that correct?
