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Zumit Ds 007

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Zumit Ds 007 [#permalink]

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New post 05 Sep 2008, 21:01
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A
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C
D
E

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Is |x - z| > |x - y| ?

(1) |z| > |y|
(2) 0 > x

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Re: Zumit Ds 007 [#permalink]

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New post 05 Sep 2008, 21:31
dancinggeometry wrote:
Is |x - z| > |x - y| ?

(1) |z| > |y|
(2) 0 > x



E

scenario 1: x = -1 , y = -4, z = -5, then |x - z| > |x - y|

scenario 2: x = -1, y= 4, z = -5, then NOT |x - z| > |x - y|

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Re: Zumit Ds 007 [#permalink]

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New post 05 Sep 2008, 21:44
dancinggeometry wrote:
Is |x - z| > |x - y| ?

(1) |z| > |y|
(2) 0 > x


(2) if x<0
question : |z-x|>|y-x| => z,y unknown cannot say INSUFFI

(1)|z|>|y| => say z=-2 ,y=-1 x=-1 => |x - z| > |x - y| is true

when z=3 x=1 ,y=-2 => |x - z| > |x - y| is false

(1) and (2) => SUFFI
x is always -ve ,hence since |z|>|y| |z-x|>|y-x|

IMO C
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Re: Zumit Ds 007 [#permalink]

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New post 06 Sep 2008, 11:43
C cannot be correct:

take for instance

x = -5
z = -2
y = -1

Here |-5 -2 | > |-5 - (-1)|

|-7| > |-4|

x = -5
z = -2
y = 1

Here |-5 -(-2) | > |-5 - 1|

|-3| < |-6|

Hence Answer is E

Another way IMO to do this is by plotting numbers on a number line

I z II y III 0 IV y V z VI
<---|-------|-----|----|------|--------->

x could be in any of I through VI

In various scenarios the distance between x and z could be greater or less than the distance between x and y

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Re: Zumit DS 007 [#permalink]

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New post 06 Sep 2008, 22:42
OA is E.

Statement (1) is not sufficient. Consider, for example, the following: if x,y, and z are -3, 4,and 5,
|x-z|=8 and |x-y|=7
BUT if x, y, and z were -3, 4, and -5, then
|x-z|=2 and |x-y|=7
In both cases, |z|>|y|, but the answer to the original question changes.

Statement (2) is not sufficient either. We know that x is negative, but we are told nothing about y and z

Combined, the statements are still insufficient. In both cases used for (1), x is negative, but we get different answers to the question.

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Re: Zumit Ds 007 [#permalink]

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New post 07 Sep 2008, 09:50
ok spriya,
i suggest u understand what is being asked.
the stem asked is (the distance betn x and z) |x - z| > |x - y|(distance betn x and y) ??

stat 1) |z| > |y|. this means that the dist betn 0 and z > dist betn 0 and y.
__________-2(z)__________-1____(x)_____0__________y(1)______________clearly x can be equidistant from both y and z. insuff.

stat 2) x is -ve . we can use the above example itself to refute the requirement.

both stat will not help
E

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Re: Zumit Ds 007 [#permalink]

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New post 07 Sep 2008, 17:15
arjtryarjtry wrote:
ok spriya,
i suggest u understand what is being asked.
the stem asked is (the distance betn x and z) |x - z| > |x - y|(distance betn x and y) ??

stat 1) |z| > |y|. this means that the dist betn 0 and z > dist betn 0 and y.
__________-2(z)__________-1____(x)_____0__________y(1)______________clearly x can be equidistant from both y and z. insuff.

stat 2) x is -ve . we can use the above example itself to refute the requirement.

both stat will not help
E

ok !
i think i got to substitute values !!!
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Re: Zumit Ds 007 [#permalink]

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New post 07 Sep 2008, 22:44
For such questions, number line helps me understand better.

Stmt 1 and 2 independently are not sufficient.

Combining the two.

Case 1: y and z are to the right of 0

!----------!---------!-------!
X 0 Y Z

In this case |z-x| > |y-x|

Case 2: y and z are to the left of 0 (and say to the left of x)

!----------!---------!-------!
Y Z X 0

Here |z-x| < |y-x|

Case 3: y and z are to the left of 0 (and say to the right of x)

!----------!---------!-------!
X Y Z 0

Here |z-x| > |y-x|

Thus, cobining two statements also gives different results. Hence, E.

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Re: Zumit Ds 007 [#permalink]

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New post 08 Sep 2008, 00:20
dancinggeometry wrote:
Is |x - z| > |x - y| ?

(1) |z| > |y|
(2) 0 > x


Can we write |x - z| as |x| - |z| ? I guess No.
So if we know only that |z| > |y| can we safely assume that the given information is insufficient ?

Thanks
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Re: Zumit Ds 007 [#permalink]

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New post 08 Sep 2008, 00:26
amitdgr wrote:
dancinggeometry wrote:
Is |x - z| > |x - y| ?

(1) |z| > |y|
(2) 0 > x


Can we write |x - z| as |x| - |z| ? I guess No.
So if we know only that |z| > |y| can we safely assume that the given information is insufficient ?

Thanks

|x-z| = |x| - |z| will not always be true. This will be true only if both x and z are positive or both are negative and x > z.

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Re: Zumit Ds 007   [#permalink] 08 Sep 2008, 00:26
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