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Sub 505 (Easy)|   Arithmetic|      
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Bunuel
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0.250/0.333 divided by 0.125/0.167 is most nearly 21 Feb 2018, 23:12
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C
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5% (low)

Question Stats:

86% (00:58) correct 14% (01:21) wrong based on 117 sessions

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\(\frac{0.250}{0.333}\) divided by \(\frac{0.125}{0.167}\) is most nearly

(A) 10

(B) 5

(C) 1

(D) 0.667

(E) 0.500
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C
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0.250/0.333 divided by 0.125/0.167 is most nearly 21 Feb 2018, 23:31
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Bunuel
\(\frac{0.250}{0.333}\) divided by \(\frac{0.125}{0.167}\) is most nearly

(A) 10

(B) 5

(C) 1

(D) 0.667

(E) 0.500
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0.250/0.333 / 0.125/0.167 = .250/.333 * .167/.125 = 2/2 ~ 1


(C) imo
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0.250/0.333 divided by 0.125/0.167 is most nearly 22 Feb 2018, 01:21
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Bunuel
\(\frac{0.250}{0.333}\) divided by \(\frac{0.125}{0.167}\) is most nearly

(A) 10

(B) 5

(C) 1

(D) 0.667

(E) 0.500
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Simplifying the numerator, \(\frac{0.250}{0.333} = \frac{2(0.125)}{2(0.167)} = \frac{0.125}{0.167}\)

Now, when \(\frac{0.125}{0.167}\) is divided by \(\frac{0.250}{0.333}\) which has been simplified to \(\frac{0.125}{0.167}\), we will get \(\frac{0.125}{0.167} * \frac{0.167}{0.125} = 1\)

Therefore, the value is nearly 1(Option C)
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0.250/0.333 divided by 0.125/0.167 is most nearly 22 Feb 2018, 10:30
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answer is C

\(\frac{0.250}{0.333}\) =\(\frac{1}{4}\)/\(\frac{1}{3}\) = \(\frac{3}{4}\)

\(\frac{0.125}{0.167}\) =\(\frac{1}{8}\)/\(\frac{1}{6}\) = \(\frac{3}{4}\)

\(\frac{3}{4}\) / \(\frac{3}{4}\) = 1
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0.250/0.333 divided by 0.125/0.167 is most nearly 22 Feb 2018, 11:59
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0.250/0.333 / 0.125/0.167

= .250/.333

---1
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0.250/0.333 divided by 0.125/0.167 is most nearly 22 Feb 2018, 12:24
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don't complicate
that's 1/4 * 3/1 = 3/4 divided by 6/8 or 3/4
that is 3/4 * 4/3 = 1
C
pretty straightforward if you know how to convert the decimals into fractions.
C
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0.250/0.333 divided by 0.125/0.167 is most nearly 22 Feb 2018, 20:52
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If we cancel out the numerator and denominator , we will get 2/2 which is 1

Ans: C
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0.250/0.333 divided by 0.125/0.167 is most nearly 23 Feb 2018, 00:35
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Bunuel
\(\frac{0.250}{0.333}\) divided by \(\frac{0.125}{0.167}\) is most nearly

(A) 10

(B) 5

(C) 1

(D) 0.667

(E) 0.500
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IMO C as 250*167/333*125
=2*167/333
=334/333 approx 1
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0.250/0.333 divided by 0.125/0.167 is most nearly 26 Feb 2018, 10:47
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Bunuel
\(\frac{0.250}{0.333}\) divided by \(\frac{0.125}{0.167}\) is most nearly

(A) 10

(B) 5

(C) 1

(D) 0.667

(E) 0.500
Show more


Recall that 0.250 = ¼, 0.125 = ⅛, 0.333 ≈ ⅓ and 0.167 ≈ ⅙, therefore,

(0.250/0.333) / (0.125/0.167) ≈ (¼/⅓)/(⅛/⅙) = (¼ x 3)/(⅛ x 6) = (¾)/(¾) = 1

Answer: C
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