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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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The other approach is to think in terms of White:
If there are 3 whites and they are never together - then out of 6, they will either take all odd places or all even places
White in odd places:
The other 3 remaining place will be taken by 1 Red and 2 Blue. So an arrangement of 3 with 2 things similar: 3!/2!

White in even places:
Exactly same logic: 3!/2!

Total: 3!/2! + 3!/2! = 6

More GMAT Permutation question solutions: https://www.youtube.com/watch?v=erIPmYF ... eRefresh=1
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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