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1/y^(1/3) = ?

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Bunuel
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1/y^(1/3) = ? [#permalink] New post  08 Sep 2021, 04:37
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A
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D
E

Difficulty:

25% (medium)

Question Stats:

76% (01:25) correct 24% (01:18) wrong based on 76 sessions

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\(\frac{1}{\sqrt[3]{y}} =?\)


A. \(\sqrt[3]{y}\)

B. \(\sqrt[3]{y^2}\)

C. \(\frac{\sqrt[3]{y}}{y}\)

D. \(\frac{\sqrt[3]{y^2}}{y^2}\)

E. \(\frac{\sqrt[3]{y^2}}{y}\)
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Re: 1/y^(1/3) = ? [#permalink] New post  08 Sep 2021, 10:40
\(\frac{1}{y^(1/3)} =\frac{ y^(2}{3)/y}\)

IMO OA should be E
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1/y^(1/3) = ? [#permalink] New post  30 Jan 2023, 05:13
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↧↧↧ Weekly Video Solution to the Problem Series ↧↧↧




We need to simplify \(\frac{1}{\sqrt[3]{y}}\)

Let's take each answer choice and see which one simplifies to \(\frac{1}{\sqrt[3]{y}}\)

\(\frac{1}{\sqrt[3]{y}}\) = \(y^{\frac{-1}{3}}\)

A. \(\sqrt[3]{y}\) = \(y^{\frac{1}{3}}\) ≠ \(y^{\frac{-1}{3}}\) => FALSE

B. \(\sqrt[3]{y^2}\) = \(y^{\frac{2}{3}}\) ≠ \(y^{\frac{-1}{3}}\) => FALSE

C. \(\frac{\sqrt[3]{y}}{y}\) = \(y^{\frac{1}{3} - 1}\) = \(y^{\frac{-2}{3}}\) ≠ \(y^{\frac{-1}{3}}\) => FALSE

D. \(\frac{\sqrt[3]{y^2}}{y^2}\) = \(y^{\frac{2}{3} - 2}\) = \(y^{\frac{-4}{3}}\) ≠ \(y^{\frac{-1}{3}}\) => FALSE

E. \(\frac{\sqrt[3]{y^2}}{y}\) = \(y^{\frac{2}{3} - 1}\) = \(y^{\frac{-1}{3}}\) => TRUE

So, Answer will be E
Hope it helps!

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1/y^(1/3) = ? [#permalink]
30 Jan 2023, 05:13
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