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bmwhype2
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gmatraider
Can anyone expalin why it is 10c2? what about the wording suggests the 2? thanks.

paraphrase our question:

How many unique pairs can we choose from 10 people regardless order in a pair?

\(C^{10}_2\)
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A handshake is performed between "TWO" ppl..to hands are needed to perform a handshake..so out of 10 ppl we have to choose 2 who will shake hands..So,10c2
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These things used to confuse me until I learned about Anagram.
It's like rearranging the alphabet HHNNNNNNNN

H represents handshake
N represents no handshake

So how many ways we can get two people handshaking in a group of 10 people?

10!/2!8!= 10x9/2 = 9x5 =45
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10C2 = 10!/8!2! = 90/2 = 45
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Number of people required for a handshake = 2
so, number of people available for one side = 10
Number of people available to complete the pair = 9

Here pair AB is the same as BA
so, 10 x 9 /2
45



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