10 years ago, Jack was twice as old as Renee. Two years from now, Jack

Question

10 years ago, Jack was twice as old as Renee. Two years from now, Jack will be 1.5 times as old as Renee. What was the sum of the ages of Jack and Renee 5 years ago?

A. 28
B. 36
C. 46
D. 50
E. 56

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Adit_ · Answer

J-10 = 2 
J+2 = 1.5

Solving both equations you get J=34, R=22.

Sum of their ages 5 years ago = 34+22-10 = 46.

Answer:  Option C

chloreton · Answer

Consider current age of Jack = J
current age of R = R

10 years ago, their age will be (J - 10) & (R - 10)
They have said, 10 years ago Jack was twice as old as Reene ie., (J-10) = 2*(R-10) ------ Equation 1

2 years from now, their age will be (J+2) & (R+2)
They have said, 2 years from now, Jack will be 1.5 times as old as Reene ie., (J+2) = 1.5*(R+2) --------Equation 2

Solving equation 1 & 2, we get J=34 ; R =22

Now, we have been asked their sum of ages 5 years ago.
Therefore (34-5)+(22-5) = 46.

Option C

vasu1104 · Answer

say current age of jack = x
current age of renee = y

10 years ago, (x-10) = 2 (y-10)
we get, x = 2y - 10

now two years from now,
(x+2) = 1.5 (y+2)
we know x= 2y-10. we can use that and find the value of y.
2y-10+2 = 1.5y + 3
we get, y= 22

x = 2y -10 = 2(22)-10 = 34

so current age of jack = 34 and renne = 22

so ten years ago, y=12 and x= 24
so five years ago, y= 17 and x= 29
the sum = 46

choice C

thisisakr · Answer

Let Jack's current age = J and Renee's current age = R.
10 years ago: J - 10 = 2(R - 10), which gives J - 10 = 2R - 20, so J = 2R - 10.
Two years from now: J + 2 = 1.5(R + 2), which gives J + 2 = 1.5R + 3, so J = 1.5R + 1.
Setting equal: 2R - 10 = 1.5R + 1, so 0.5R = 11, giving R = 22.
Then J = 2(22) - 10 = 34.
Five years ago, Jack was 34 - 5 = 29 and Renee was 22 - 5 = 17.
The sum of their ages 5 years ago was 29 + 17 =  46 .

Answer  C

ExpertsGlobal5 · Answer

C is the correct answer choice.

Video explanation:

https://www.youtube.com/watch?v=Fgl4UjfYjdI

10 years ago, Jack was twice as old as Renee. Two years from now, Jack

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