Rita has a bowl containing three types of candies: cherry, mango, and lime. If there are 82 candies in total, out of which 29 are cherry, how many mango candies are in the bowl?
(1) The minimum number of candies Rita must pick at random from the bowl to ensure getting at least one candy of each flavor is 69.
(2) There are fewer lime candies than mango candies.
Solution:
C+M+L = 82 and C = 29, which means M+L = 53
(1) The minimum number of candies Rita must pick at random from the bowl to ensure getting at least one candy of each flavor is 69.
In order to get at least one candy, we need to select all candies of those two type candies which have highest candies and then add one candy of another type.
Since M+L = 53, which means both cannot be more than 29. That means one type has less candies than Cherry.
So, M or L + Cherry (C=29) + 1 = 69
M or L = 69 - 29 - 1
M or L = 39
Hence this statement is not sufficient.
(2) There are fewer lime candies than mango candies.
This will have multiple cases M or L = (1 or 52 / 52 or 1; 20 or 33/ 33 or 20, etc.)
If we combine both the statement, in that case we have one pair only M or L = (39 or 14 / 14 or 39)
Since Statement2 states that there are fewer line candies which means L = 14 and M = 39.
So option C is correct answer.