Last visit was: 21 May 2026, 22:06

It is currently 21 May 2026, 22:06

Toolkit

Practice Tests

Quantitative Questions

Problem Solving (PS)

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more

Request Expert Reply

Confirm Cancel

May 22
MBA in Europe: LBS & INSEAD Alumni on Choosing Europe Over the US
08:30 AM PDT
-
09:30 AM PDT
For many Indian MBA applicants, the default dream has long been a top US MBA. But as career goals, visa considerations, timelines, and global mobility priorities evolve, more candidates are seriously considering MBA programs in Europe.
May 21
Summer savings start now on Manhattan Prep Courses!
10:00 AM EDT
-
11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
Jun 10
MBA Spotlight Fair
06:00 AM PDT
-
06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..

Back to Forum

Create Topic

12 Days of Christmas GMAT Competition 2025 - Day 6: At a professional

1 2 3 4

AviNFC

Joined: 31 May 2023

Last visit: 10 Apr 2026

Posts: 306

Own Kudos:

366

[1]

Given Kudos: 5

Posts: 306

Kudos: 366

[1]

22 Dec 2025, 11:01

Kudos

Bookmarks

only NT=x
only DA=6x
both NT & DA but not PM =p
only PM=12 p

given: x= 0.25*12p =3p
12p+k=220

so, 7x+p+220=308; x=3p
p=4

reqd only one= 7x+12 p =33p = 33*4 =132

Ans D

linnet

Joined: 11 Dec 2025

Last visit: 22 Jan 2026

Posts: 81

Own Kudos:

[1]

Given Kudos: 1

Posts: 81

Kudos: 42

[1]

22 Dec 2025, 11:08

Kudos

Bookmarks

Only P.M- X
NT- Y
DA- Z
DA+NT= A
only PM= 12(A) Total PM IS 220 & Total Participants= 308
None PM are, only DA= Z
Only NT = 3A
only DA+NT= A
Z+3A+A=Z+4A since Total PM is 220 , Z+4A=308-220=88
Z= 88-4A So only PM+ only NT +only DA= 12A+3A+(88-4A)= 11A+88
we find valid integer values of A- lets test small valid values
try A= 4 so only PM=48, Only NT=12, Only DA= 88-16= 72
Exactly one program will e 48+12+72= 132
Final answer is 132

Xdsa

Joined: 07 Jul 2025

Last visit: 08 May 2026

Posts: 58

Own Kudos:

[1]

Given Kudos: 1

Posts: 58

Kudos: 45

[1]

22 Dec 2025, 11:09

Kudos

Bookmarks

only data analysis =18x
only project management =12x
only negotiation=3x
data analysis and negotiation only=x
project management= 220
remaining is 88
18x + 3x + x=88
x=4
exactly 1 = (12+3+18)x =33.4=132 is the answer

arnab24

Joined: 16 Jan 2024

Last visit: 25 Feb 2026

Posts: 96

Own Kudos:

[1]

Given Kudos: 7

Location: India

Schools: ISB '26

GPA: 8.80

Schools: ISB '26

Posts: 96

Kudos: 81

[1]

22 Dec 2025, 11:19

Kudos

Bookmarks

Let x be the number of participants attending only Negotiation training. 6x will be the number of participants attending only Data Analysis. Further let y be the number of participants attending both Data Analysis and Negotiation but not project management. 12y will be the number of participants attending only Project Management. Further , the number who attended only Negotiation Training was one-quarter of the number who attended only Project Management.

So , x = 0.25*12y = 3y

if 220 participants attended the project management workshop , then we need to find the number of participants attended exactly of the three workshops (z):

z= 6x+x+12(x/3) = 7x+4x = 11x

220 = 308-6x-x/3-x

x=12

z=12*11 = 132

So , answer is 132.

Bunuel

At a professional conference, 308 participants signed up for at least one of three evening workshops: Data Analysis, Project Management, and Negotiation Training. Exactly six times as many participants attended only Data Analysis as attended only Negotiation Training. The number of participants who attended only Project Management was twelve times the number who attended both Data Analysis and Negotiation Training but not Project Management. The number who attended only Negotiation Training was one-quarter of the number who attended only Project Management. If 220 participants attended the Project Management workshop, how many participants attended exactly one of the three workshops?

A. 48
B. 88
C. 120
D. 132
E. 136

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

gemministorm

Joined: 26 May 2025

Last visit: 19 May 2026

Posts: 143

Own Kudos:

114

[1]

Given Kudos: 57

GMAT Focus 1: 565 Q82 V79 DI73 Verified score

GMAT Focus 2: 605 Q84 V83 DI73 Verified score

Posts: 143

Kudos: 114

[1]

22 Dec 2025, 11:36

Kudos

Bookmarks

Acc. to question - 308 participants signed for at-least one DA/PM/NT -> none = 0.
let us assume only NT = x, DA & NT but not PM = y (this is for one of the statements mentioned in the question)
Given: DA only = 6x, PM only = 12y and x = 12y/4 = 3y -- (i)
also apart from 220 remaining from 308 are 6x (DA only) + x (NT only) + y (DA & NT but not PM) = 7x + y = 308 ---(ii)
from (i) and (ii) we get y = 4.
we need to find -> exactly 1 of 3 -> x (NT only) + 6x (DA only) + 12y (PM only) = 7x + 12y = 132

flippedeclipse

Joined: 26 Apr 2025

Last visit: 18 May 2026

Posts: 105

Own Kudos:

[1]

Given Kudos: 38

GMAT Focus 1: 655 Q80 V87 DI80 Verified score

Products:

GMAT Focus 1: 655 Q80 V87 DI80 Verified score

Posts: 105

Kudos: 73

[1]

22 Dec 2025, 11:49

Kudos

Bookmarks

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

Image attached/at this link for reference (image uploader is not cooperating so apologies if it's double-posted).https://ibb.co/Kp4wCQLm

x, y and z represent those who only attended that session.

From the lengthy stem we know that:
$x=\frac{1}{4}y=3a$
$z=6x=18a$
$y=12a$

We're looking for $x+y+z$. From the above equations, it becomes clear that unlocking a value for A will help unlock this sum.

If 220 people attended the project management session, it follows that $308-220=88$ did not attend the project management session.

Using the diagram, that means $88=x+a+z=3a+a+18a$, thus $a=4$.

$x+y+z=33a=132$

Thus, D is the answer.

batman10bigman

Joined: 23 Apr 2025

Last visit: 21 May 2026

Posts: 44

Own Kudos:

[1]

Given Kudos: 12

Products:

Posts: 44

Kudos: 38

[1]

22 Dec 2025, 12:14

Kudos

Bookmarks

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

Let the categories be:
D only = d
P only = p
N only = n
D & P only = x
D & N only = y
P & N only = z
All three = t

For exactly six times as many participants attended DA as attended only NT:
d = n

Only PM was twelve times the number who attended both DA and NT but not PM:
p = 12y

Only NT was one quarter of only PM:
n = (1/4)p

from these, we get
n = 3y
d = 6n = 18y
p = 12y

PM total is 220:
p + x + z + t = 220

Total participants is 308:
d + p + n + x + y + z + t = 308

substitute d, p ,n in terms of y:
18y + 12y + 3y + x + y + z + t = 308
34y + x + z + t = 308

Subtract the P equation:
(34y + x + z + t) - (12y + x + z + t) = 308 - 220
22y = 88 => y = 4

n = 3y = 12
d = 18y = 72
p = 12y = 48

Participants who attended exactly one workshop:
d + p + n = 72 + 48 + 12 = 132

Option D

canopyinthecity

Joined: 12 Jul 2025

Last visit: 21 May 2026

Posts: 93

Own Kudos:

[1]

Given Kudos: 19

Posts: 93

Kudos: 61

[1]

22 Dec 2025, 12:28

Kudos

Bookmarks

Let

numbers of participants in only NT be x
then number of participants in only DA = 6x

number of participants in both NT and DA and not PM be y
then number of participants for only PM = 12y
total PM = 220

x = 1/4 of 12y = 3y (eq 2)

Equation:

x+6x+y+220 = 308
Solving using eq 2, y =4

We have to find, x+6x+12y = 33y = 132

Hence (D) is the answer

pappal

Joined: 24 Nov 2022

Last visit: 21 May 2026

Posts: 336

Own Kudos:

110

Given Kudos: 115

Products:

Posts: 336

Kudos: 110

22 Dec 2025, 12:47

Kudos

Bookmarks

since given n(none)=0
so E1+E2+E3=308 (union of the set)-----i
let P, Po, Do, No, (D&N)o represents n(project), n(project only), n(data only), n(negotiation only), n(data & negotiation only) respectively.
from conditions given P=220
Do=6*No=6x let-------ii
Po=12*(D&N)o=12y let-------iii
and No=1/4*12y=3y--------iv
from ii & iv , x=3y
so Do=18y, Po=12y & No=3y
i.e. exactly one E1 =18y+12y+3y=33y----v
and at least two=E2+E3=P - Po + (D&N)o=220-12y+y=220-11y----------vi
from i , v and vi
308 - 33y= 220-11y
22y=88 or y=4
so E1=33*4=136
so E (can be solved fast when represented on a venn diagram)

Natansha

Joined: 13 Jun 2019

Last visit: 11 Mar 2026

Posts: 195

Own Kudos:

[1]

Given Kudos: 84

Posts: 195

Kudos: 65

[1]

22 Dec 2025, 12:54

Kudos

Bookmarks

I solved it using venn diagram, attaching it's picture for reference (why is it so difficult to attach a picture). We have total = 308, Neither = 0

a+b+c+f = 220
g = 6e
f = 12b
e = 1/4 f

we need g+e+f?

a+b+c+d+e+f+g = 308
220 +b+e+g = 308

putting in b,e & g in terms of f, using above

f/12 + f/4 + 6/4 f = 88
22f = 1056
f = 48

Hence g + e + f = 48 +12 + 72 = 132

Attachments

IMG_7192-2.jpg [ 100.29 KiB | Viewed 404 times ]

chasing725

Joined: 22 Jun 2025

Last visit: 13 Jan 2026

Posts: 176

Own Kudos:

174

[1]

Given Kudos: 5

Location: United States (OR)

Schools: Stanford

Posts: 176

Kudos: 174

[1]

22 Dec 2025, 13:50

Kudos

Bookmarks

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

We can draw an overalpping set

Only DA = a
Only PM = b
Only NT = c

Both DA and PM = d + g

Both DA and NT = d + g + e

Both NT and PM = e + g + f

All three = g

Given a = 6c
b = 12e
c = 1/4 b

a + b + c + d + e + f + g = 308

b + d + g + f = 220

a + c + e = 88

6c + c + c/3 = 88

c = 12

a = 72

b = 48

c + b + a= 132

Option D

Fisayofalana

Joined: 26 Sep 2017

Last visit: 14 Apr 2026

Posts: 51

Own Kudos:

[1]

Given Kudos: 55

Location: United States

Schools: Booth '26 HBS '26 Darden '26 CBS '26 Tuck '26 Wharton '26 Johnson '26

Posts: 51

Kudos: 9

[1]

22 Dec 2025, 13:54

Kudos

Bookmarks

I filled out my Venn diagram with the following:

Data Analysis only = 6X
Project Management Only = 12Y
Negotiation Training = X = 1/4(12Y)

Data Analysis and Negotiation Training = Y

Now I just solved to make every space in the Venn diagram the same variable.

Only Data Analysis is 18Y
Only Project Management is 12Y
Only Negotiation Training is 3Y.

Together it sums up to 33Y. I looked at the answer choices to see which is a multiple of that. Answer 132.

jefferyillman

Joined: 01 Dec 2024

Last visit: 21 May 2026

Posts: 50

Own Kudos:

[1]

Given Kudos: 3

Posts: 50

Kudos: 27

[1]

22 Dec 2025, 16:43

Kudos

Bookmarks

Answer D

data analysis only = D
project management only = P
Negotiation Training only = N
data and negotiation = x

D = 6N
P = 12x
4N = P

Project management total = P only + (P+D) + (P+N) = 220

308 (attend at least one) = D + P+ N + DN(x) + PN + PD - PDN
308 = 220 + D + N + DN - PDN
308 = 220 + 6N + N + x - PDN

Only D = 72
Only P = 48
only N =12

total 132

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

poojaarora1818

Joined: 30 Jul 2019

Last visit: 21 May 2026

Posts: 1,634

Own Kudos:

788

Given Kudos: 3,858

Location: India

Concentration: General Management, Economics

Schools: Kellogg Emory Goizueta Marshall

GPA: 3

WE:Human Resources (Real Estate)

Products:

Schools: Kellogg Emory Goizueta Marshall

Posts: 1,634

Kudos: 788

22 Dec 2025, 19:19

Kudos

Bookmarks

Solution:

Signed up at least one of the three workshop = 308
Project Managemnet = 12(Data Analysis+Negotiation Training)
Negotiation Training = 1/4PM
Total PM = 220

NT = 1/4*220=55
We have now PM as 220 and NT as 55. So, if we subtract 275 from 308 we get 88 as our answer.

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

aka007

Joined: 15 Nov 2019

Last visit: 19 Mar 2026

Posts: 42

Own Kudos:

[1]

Given Kudos: 84

Posts: 42

Kudos: 37

[1]

22 Dec 2025, 20:29

Kudos

Bookmarks

Will need to make a pie diagram with all three intersecting each other.
Let x,y,z be only DA, only PM and only NT respectively.

The intersection between
both DA and PM: c
both DA and NT: a
both NT and PM: b

The intersection between all three is d.

Given.

x=6z
y=4z
z=z
y=12a=> 4z=12a=> a=z/3
c+b+d+y( which is 4z)=220=> c+b+d+4z=220 => c+b+d=220-4z

all are having some relation with z

also given
x+y+z+a+b+c+d=308
which can be substituted and written as
11z+z/3+220-4z=308

hence z=12

question is asking exactly one i.e. x+y+z= 11z= 11x12=132

Ans is D

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

Aarushi100

Joined: 17 Jul 2024

Last visit: 21 May 2026

Posts: 61

Own Kudos:

[1]

Given Kudos: 96

Posts: 61

Kudos: 49

[1]

22 Dec 2025, 21:11

Kudos

Bookmarks

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

Let the number of attendees:
Only Data Analytics (DA): a
Only Project Management(PM): b
Only Negotiation Training (NT): c
DA and NT but not PM: x

According to the ratios given:

1. a=6c
2. b=12x
3. b=4c

We have to find a+b+c=?
Total of PM = 220.
Total = 308
Now, if we remove the total of PM from the total we will get the value of a+c+x:
=> a+c+x=308-220
a+c+x=88
6c+c+c/3=88
22c/3=88

c=12
=> b=48
=> a= 72
a+b+c= 72+48+12= 132

Answer D. 132

jai169

Joined: 25 May 2024

Last visit: 22 Mar 2026

Posts: 10

Own Kudos:

[1]

Given Kudos: 3

Posts: 10

Kudos: 7

[1]

22 Dec 2025, 22:40

Kudos

Bookmarks

total participant=T.p=308
ONLY negotiation training=ONA= x
only data anaylsis=O.DA= 6x
number of participants who only attended both data analysis and negotiation training but not project managment=y
Number of parti who attended only project managment=OPA=12 y
the number who attended only negotiation training= 1/4(12y)=3y
total no of people attending the project managment workshop is =220
remaining people= who attended only DA(6x)+who attended only negotiation training(ONA(x)+who attended both negotition and DA but not project managment(Y)=308-220=88
6x+x+y=88
7x+y=88
21y+y=22y=88
y=4
The number who attended only negotiation training was one quarter of the number who attended only project management =x=3y
so question asks how many attended exactly one of three workshop which is= ONA+ODA+OPA=12y+7x=12y+7(3y)=12y+21y=33y=33(4)=132
ans is option D 132

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

truedelulu

Joined: 01 Sep 2025

Last visit: 24 Jan 2026

Posts: 81

Own Kudos:

[1]

Given Kudos: 16

Posts: 81

Kudos: 70

[1]

22 Dec 2025, 22:47

Kudos

Bookmarks

Let 6x, x be the number of participants in only Data Analysis (D) and only Negotiation (N) respectively.
Let 12a, x be the number of participants in only Project Management (P) and only D+N respectively.

From the given information:
x = 1/4 * 12a = 3a => 6x = 18a

It's better to draw a Venn chart to visualize so i attach the image.

Total participants = 308 = 18a + 3a + a + 220 => a = 4

Exactly one = 18a + 3a + 12a = 33a = 33*4 = 132

Answer: D

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more

Attachments

1d85a4ef-13e0-4d4b-98ad-3950da2ca24d.jpg [ 321.32 KiB | Viewed 360 times ]

Rahilgaur

Joined: 24 Jun 2024

Last visit: 26 Jan 2026

Posts: 162

Own Kudos:

125

[1]

Given Kudos: 47

GMAT Focus 1: 575 Q81 V82 DI72 Verified score

Products:

GMAT Focus 1: 575 Q81 V82 DI72 Verified score

Posts: 162

Kudos: 125

[1]

22 Dec 2025, 23:20

Kudos

Bookmarks

Attachments

IMG_0426.jpeg [ 3.1 MiB | Viewed 347 times ]

gchandana

Joined: 16 May 2024

Last visit: 20 May 2026

Posts: 203

Own Kudos:

148

[1]

Given Kudos: 172

Location: India

Products:

Posts: 203

Kudos: 148

[1]

22 Dec 2025, 23:27

Kudos

Bookmarks

Data analysis only = d
Negotiation Training only = n
Project management only = p

Given, d = 6n
Then, if people who attended both data analysis and negotiation training but not project management = a, then given p = 12a.
Also given n = 12a / 4, so n = 3a, then d = 18a.

For the number of participants who attended exactly one = d + n + p = 18a + 3a + 12a = 33a. Note here that a is an integer, so the needed answer is a multiple of 33. Only one option satisfies this: 132.

Option D.

Bunuel

Gift

12 Days of Christmas Competition

This question is part of our holiday event

Win $40,000 in prizes: courses, tests, and more