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Bunuel
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Answer A - Statement 1 Alone is sufficient

Explanation:
From the Question - Assuming the duration of toy-making competition was 'T' hrs
Elvin's rate of toy making Re = 75/T toys per hr.
Nori's rate of toy making Rn = 60/T toys per hr.
Any additional info on the rate of toy making will help with solving the Problem.

Statement Analysis
Statement 1 : Rn = Re - 5 => 60/T = 75/T - 5 => solve for T , 1 is sufficient
Statement 2 : Ratio of Re and Rn is given -> which is already available from the question statement thus this does not provide additional info for the Time variable 'T' , statement 2 is not sufficient.

Answer is A.
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Question: Time of the competition (T=?)
Given info: # of toys that each made: We= 75 (toys made by Elvin) & Wn = 60 (toys made by Nori)
T = Time of competition
Re = Rate of Elvin
Rn = Rate of Nori

Analyze given info:
* Work Rate problem formula: Work = Rate * time => Time = Work/Rate
* Since E & N in a competition, Timing for both is the same => T = Te = Tn => We/Re = Wn/Rn
=> 75/Re = 60/Rn => Re/Rn =75/60=5/4
=> Any info that can calculate Re or Rn will give the answer

Now look at the additional information in (1) & (2)
(1) During the competition, Nori the elf's toy crafting rate was 5 toys per hour slower than Elvin the elf's.
=> Rn = Re - 5 => Re/(Re -5) = 5/4
=> Re = 25
=> T = 75/25 = 3 hours
=> Suf.

(2) During the competition, the ratio of Elvin the elf's average toy crafting rate to Nori the elf's average toy crafting rate was 5 to 4.
=> Same with original analyze result => not suf.

=> Ans: A
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Hi sir

I know it's been more than an year for this reply/answer, but as more people will be watching & analyzing this; I wanted to correct a typo here.

In the breakdown of (1), in equation you have mention e + 5 whereas it should be e - 5. pls fix it.

Thanks.
- Sai Krishna A

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Bunuel
12 Days of Christmas 🎅 GMAT Competition with Lots of Questions & Fun

During a festive Christmas Eve toy-making competition, Elvin the elf crafted 75 toys, while Nori the elf crafted 60 toys. How long did the toy-making competition last?

(1) During the competition, Nori the elf's toy crafting rate was 5 toys per hour slower than Elvin the elf's.
(2) During the competition, the ratio of Elvin the elf's average toy crafting rate to Nori the elf's average toy crafting rate was 5 to 4.

 


This question was provided by GMAT Club
for the 12 Days of Christmas Competition

Win $40,000 in prizes: Courses, Tests & more

 


(1) During the competition, Nori the elf's toy crafting rate was 5 toys per hour slower than Elvin the elf's.

Rate of Elvin = e

Rate of Nori = e - 5

At the end of the competition both used the same time

\(\frac{75}{e} = \frac{60}{e+5}\)

Solving for e we get, e = 25

Hence, the competition lasted for 75/25 = 3 hours. Statement 1 is sufficient.

(2) During the competition, the ratio of Elvin the elf's average toy crafting rate to Nori the elf's average toy crafting rate was 5 to 4.

Rate of Elvin = e

Rate of Nori = 4/5 e

\(\frac{75}{e} = \frac{60}{4/5e}\)

We can cancel the rate out, hence the statement will not have any variable to calculate. The statement is not sufficient

IMO A
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Hi sir

I know it's been more than an year for this reply/answer, but as more people will be watching & analyzing this; I wanted to correct a typo here.

In the breakdown of (1), in equation you have mention e + 5 whereas it should be e - 5. pls fix it.

Thanks.
- Sai Krishna A

GMATCenturion
Bunuel
12 Days of Christmas 🎅 GMAT Competition with Lots of Questions & Fun

During a festive Christmas Eve toy-making competition, Elvin the elf crafted 75 toys, while Nori the elf crafted 60 toys. How long did the toy-making competition last?

(1) During the competition, Nori the elf's toy crafting rate was 5 toys per hour slower than Elvin the elf's.
(2) During the competition, the ratio of Elvin the elf's average toy crafting rate to Nori the elf's average toy crafting rate was 5 to 4.

 


This question was provided by GMAT Club
for the 12 Days of Christmas Competition

Win $40,000 in prizes: Courses, Tests & more

 


(1) During the competition, Nori the elf's toy crafting rate was 5 toys per hour slower than Elvin the elf's.

Rate of Elvin = e

Rate of Nori = e - 5

At the end of the competition both used the same time

\(\frac{75}{e} = \frac{60}{e+5}\)

Solving for e we get, e = 25

Hence, the competition lasted for 75/25 = 3 hours. Statement 1 is sufficient.

(2) During the competition, the ratio of Elvin the elf's average toy crafting rate to Nori the elf's average toy crafting rate was 5 to 4.

Rate of Elvin = e

Rate of Nori = 4/5 e

\(\frac{75}{e} = \frac{60}{4/5e}\)

We can cancel the rate out, hence the statement will not have any variable to calculate. The statement is not sufficient

IMO A
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