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18 Dec 2021, 07:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (01:55) correct
39%
(01:58)
wrong
based on 574
sessions
History
Date
Time
Result
Not Attempted Yet
12 Days of Christmas GMAT Competition with Lots of Fun
What is the percentage of alcohol in solution X?
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
What is the percentage of alcohol in solution X?
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
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(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
General Discussion
18 Dec 2021, 07:20
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Bunuel
Let solution X contains a litres of alcohol and w liters of water.
So total solution = a+w
% of alcohol = a/a+w *100
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
New alcohol volume = a+50
New total volume = a+50+w
Alcohol % = a+50/a+w+50 = 60/100
One equation two variables
Not sufficient. A and D are out.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
New water volume = w+a+w
New total solution = 2(a+w)
% of alcohol = a/2(a+w) = 20/100
a/a+w = 40/100
Sufficient. B is the answer.
20 Dec 2021, 06:31
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kapil1995
I am sure experts will help you better understand the flaw in your reasoning but 1 eminent flaw which I found I am mentioning.
You have taken the constant value for the total quantity of the mixture instead if you would have taken it in variable form it would have solved the problem as in in place of 100ml if you would have taken 100x. |because we don't know what actual quantity was.
Now how that's a flaw.?
Let's take your reasoning only
After addition of 50 Liters alcohol , In 100 ml , 60 alcohol & 40 Water .
Means Orignally Its 50 Ml solution with 10 ml alcohol and 40 ml water
Means 20% Alcohol in solution X. |Correct.
I am assuming after addition of 50 litres of alcohol the resultant solution becomes 150 (instead of 100), 90 alcohol & 60 Water.
Means Originally its 100ML solution with 40 alcohol and 60 Water.
Means 40% Alcohol in solution X. | Also correct.
How can there be two different values of alcohol concentration for the same solution X. | Ambiguity, which could have been solved by just taking a variable like 100x.
