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Jul 1011:00 AM PDT
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In our conversation, Kishore talks about how strategically he used data analytics to identify high impact areas to focus on as well as his early morning study routine (3 AM prep!) that optimized his GMAT preparation.- Jun 30
08:00 AM PDT
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Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates! 
Jul 0901:00 PM EDT
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More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1206:30 AM PDT
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Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
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Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
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Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
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Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
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Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
25 Dec 2024, 08:09
Kudos
Bookmarks
Let's say that \(m+b=630\)
Then tagged \( t=630*5/9=350\) and untagged \(u=630-350=280\)
As m to b in tagged is 6:1, there're 7 parts overall: so tagged birds are \(t/7=350/7=50\), and tagged mammals are \(50*6=300\)
As tagged birds are a fifth from all birds, then all birds \(b=50*5=250\)
And mammals \(m=630-250=380\), while tagged are 300
This leaves 80 untagged mammals, so the answer is B.
Then tagged \( t=630*5/9=350\) and untagged \(u=630-350=280\)
As m to b in tagged is 6:1, there're 7 parts overall: so tagged birds are \(t/7=350/7=50\), and tagged mammals are \(50*6=300\)
As tagged birds are a fifth from all birds, then all birds \(b=50*5=250\)
And mammals \(m=630-250=380\), while tagged are 300
This leaves 80 untagged mammals, so the answer is B.
25 Dec 2024, 08:51
Kudos
Bookmarks
1/5 of birds are tagged and 4/5 of birds are untagged
tagged mammals to birds 6:1 THUS, 6/7 of tagged are mammals and 1/7 of tagged are birds
6/7*350 = 300 mammals tagged and 50 birds tagged ( 1/7*350)
630 T, so 5/9T are tagged = 350 tagged and thus 630-350 = 280 of animals are untagged
1/5B are tagged and since 50 are the birds tagged then B must be 250
Continuing, 200 will be the birds that are untagged and from the untagged animals 80 will be the mammals untagged. Answer B
tagged mammals to birds 6:1 THUS, 6/7 of tagged are mammals and 1/7 of tagged are birds
6/7*350 = 300 mammals tagged and 50 birds tagged ( 1/7*350)
630 T, so 5/9T are tagged = 350 tagged and thus 630-350 = 280 of animals are untagged
1/5B are tagged and since 50 are the birds tagged then B must be 250
Continuing, 200 will be the birds that are untagged and from the untagged animals 80 will be the mammals untagged. Answer B
