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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=

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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post Updated on: 30 Oct 2018, 01:30
1
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

78% (00:59) correct 22% (01:52) wrong based on 199 sessions

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\((2^2-1)(2^2+1)(2^4+1)(2^8+1)=\)


A. \(2^{16} - 1\)

B. \(2^{16} + 1\)

C. \(2^{32} - 1\)

D. \(2^{128} - 1\)

E. \(2^{16}(2^{16}-1)\)

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Originally posted by Stiv on 05 Jul 2012, 01:26.
Last edited by Bunuel on 30 Oct 2018, 01:30, edited 2 times in total.
Edited the question.
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Re: (2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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Re: (2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post 03 Sep 2014, 01:45
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\((2^2-1)(2^2+1)(2^4+1)(2^8+1)= 2^{(2+2+4+8)} - 1 = 2^{16} - 1\)

Answer = A
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Re: (2^2 −1)(2^2 +1)(2^4 +1)(2^8 +1)  [#permalink]

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New post 30 Oct 2018, 01:23
pushpitkc wrote:
\((2^2 −1)(2^2 +1)(2^4 +1)(2^8 +1)\) =

(A) \(2^{16} −1\)
(B) \(2^{16} +1\)
(C) \(2^{32} −1\)
(D) \(2^{128} −1\)
(E) \(2^{16}(2^{16} −1)\)


\((2^2 −1)(2^2 +1)\)\((2^4 +1)(2^8 +1)\) = \((2^4 −1)\)\((2^4 +1)(2^8 +1)\)

Now, \((2^4 −1)(2^4 +1)\)\((2^8 +1)\)=\((2^8 −1)\)\((2^8 +1)\)

Now, \((2^8 −1)(2^8 +1)\) = \((2^{16} −1)\)

Answer:Option A
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Re: (2^2 −1)(2^2 +1)(2^4 +1)(2^8 +1) &nbs [#permalink] 30 Oct 2018, 01:23
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