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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=

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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post Updated on: 05 Jul 2012, 02:53
1
5
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

78% (00:56) correct 22% (01:42) wrong based on 192 sessions

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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=

A. 2^16 - 1
B. 2^16 + 1
C. 2^32 - 1
D. 2^128 - 1
E. 2^16(2^16-1)

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Originally posted by Stiv on 05 Jul 2012, 02:26.
Last edited by Bunuel on 05 Jul 2012, 02:53, edited 1 time in total.
Edited the question.
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Re: (2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post 05 Jul 2012, 02:55
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(2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post 03 Sep 2014, 02:45
2
\((2^2-1)(2^2+1)(2^4+1)(2^8+1)= 2^{(2+2+4+8)} - 1 = 2^{16} - 1\)

Answer = A
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Re: (2^2-1)(2^2+1)(2^4+1)(2^8+1)=  [#permalink]

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New post 08 Dec 2017, 09:29
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: (2^2-1)(2^2+1)(2^4+1)(2^8+1)= &nbs [#permalink] 08 Dec 2017, 09:29
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