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24 Nov 2014, 00:56
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:44) correct
36%
(01:12)
wrong
based on 56
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{{2^3}^{2} - {(2^3)}^{2}}{28}\) =
A: 0
B: \(\frac{4}{7}\)
C: 8
D: 12
E: 16
A: 0
B: \(\frac{4}{7}\)
C: 8
D: 12
E: 16
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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24 Nov 2014, 03:50
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Given that (2^3^2 - (2^3)^2)/28
solving it further as (2^9 - 2^6)/28
(512 - 64)/28
(448)/28 =16
Answer E
solving it further as (2^9 - 2^6)/28
(512 - 64)/28
(448)/28 =16
Answer E
deepaktrivedi
11 Mar 2015, 03:48
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=(2^9-(2^3)^2)/28
=(2^9-2^6)/28
=2^6(2^3-1)/28
=[(2^6)*7]/28
=2^6/4
=16
and so the answer is E
=(2^9-2^6)/28
=2^6(2^3-1)/28
=[(2^6)*7]/28
=2^6/4
=16
and so the answer is E
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
