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Bunuel
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Bunuel
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VAKRATUNDA
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Bunuel
If \(x\) is a positive number and \(2\sqrt{2}=\sqrt{\sqrt{x}-6}\), then what is the value of \(x\)?

A. \(\frac{14}{\sqrt{2}}\)
B. \(14\)
C. \(169\)
D. \(196\)
E. \(225\)

USE OPTIONS!!

\(2\sqrt{2}=\sqrt{\sqrt{x}-6}\)

Ignore A for now. It's complicated.

14 is not possible because it is not a perfect square.

C gives us x as 13. 13-6 is 7 and that's not equal to LHS.

D gives us x as 14. 14-6 is 8. Taking square root of 8 gives us \(2\sqrt{2}\) and we cannot have multiple correct answers.

So D it is.
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I've revised the question and solution, incorporating additional details for improved clarity. I trust this makes it more comprehensible.
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I like the solution - it’s helpful.
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