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You draw a marble from each bag what is the probability of drawing at least 2 blue marbles?
B W B * B W W B W R B R B * B R W B R R B B B * B B W * B B R *
W W B W W W W W R W R B W R W W R R W B B * W B W W B R
R W B R W W R W R R R B R R W R R R R B B * R B W R B R
So I marked down all of the possible outcomes and I get 7/27 but it doesn't make sense to me to include the same blue marbles twice because the third color is different So that gives me 3/27. Which one is the correct answer if any? Appreciate some help.
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This is clearly a probability question, but it is missing some vital information:
1) How many bags are there? 2) How many of each color marble are in each bag? Even if we don't have the exact number of marbles of each color, a ratio of the colors would suffice.
If you provide the missing information, then I'll be happy to assist.
Hi, I believe you are talking of 3 bags having one each of w,r,and b.... At least 2 b means... 1) all 3 b... Only one way.. b,b,b 2) 2b.. Choose two bags out of 3, which will contain b.. 3C2= 3 ways but the third one can be either r or w, so 3*2=6 ways.. So total 7
Total ways=3*3*3=27.. Ans 7/27..
So as for your Q, yes babe will be different from bbr.. Your calculations of 27 contains both bbw and bbr as different ways , so they both have to be calculated as separate in possible cases thus 7
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