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$3000 is distributed among A, B and C such that A gets 2 3 rd of w

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cfc198
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$3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  21 Feb 2019, 10:13
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Rs. 3000 is distributed among A, B and C such that A gets 2/3 rd of what B and C together get and C gets 1/2 of what A and B together get. Find B’s share.
(1) 800
(2) 1000
(3) 1200
(4) 1500
(5) 1800
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eabhgoy
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  21 Feb 2019, 13:33
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cfc198 wrote:
Rs. 3000 is distributed among A, B and C such that A gets 2/3 rd of what B and C together get and C gets 1/2 of what A and B together get. Find B’s share.
(1) 800
(2) 1000
(3) 1200
(4) 1500
(5) 1800


From the question we know:

1) A gets 2/3 rd of what B and C together get
Lets assume B+C get x
=> 2/3x + x = 3000
=> x = 1800
A gets 2/3x = 1200

2) C gets 1/2 of what A and B together get
Lets assume A+B get y
=> 1/2y + y = 3000
=> y = 2000
C gets 1/2y = 1000

Hence B gets = 3000 - 1200 - 1000 = 800

Hence A is the correct answer.
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IanStewart
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  21 Feb 2019, 14:37
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The ratio of A's share to the rest is 2 to 3, so A gets 2/5 of the total, or $1200.

The ratio of C's share to the rest is 1 to 2, so C gets 1/3 of the total, or $1000.

So B must get the remaining $800.
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jfranciscocuencag
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  01 Jul 2019, 18:12
IanStewart wrote:
The ratio of A's share to the rest is 2 to 3, so A gets 2/5 of the total, or $1200.

The ratio of C's share to the rest is 1 to 2, so C gets 1/3 of the total, or $1000.

So B must get the remaining $800.


Hello IanStewart!

Is it possible to apply this shortcutt to most of the problems related with ratios?

Kins regards!
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IanStewart
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  02 Jul 2019, 05:27
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jfranciscocuencag wrote:
Is it possible to apply this shortcutt to most of the problems related with ratios?


I'm not sure precisely what shortcut you mean, but there is so much variety in GMAT ratio problems that there could never be one shortcut that would solve 'most' problems.
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Nirmesh83
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  12 Jul 2021, 10:31
jfranciscocuencag wrote:
IanStewart wrote:
The ratio of A's share to the rest is 2 to 3, so A gets 2/5 of the total, or $1200.

The ratio of C's share to the rest is 1 to 2, so C gets 1/3 of the total, or $1000.

So B must get the remaining $800.


Hello IanStewart!

Is it possible to apply this shortcutt to most of the problems related with ratios?

Kins regards!


Hi ,
By observing Qs and POE ,answer can easily be derived without solving.

Sum of A+B+C =3000
C= (A+B)/2
So C is mean of A & B.
Numbers could be arrange like A/B, C, B/A

now, A is 2/3 of (B+C) ..i.e A is 66% of sum of rest of numbers.

We can derive that , numbers will be arrange as B,C,A.
Value of C is 1000 (From equn. A+B/2). Therefore , only option 800 is feasible out of given options.
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rvgmat12
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  13 Jul 2021, 04:58
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A = (3000-A)*2/3

A = 1200

2C = 3000-C

C = 1000

B = 800
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink] New post  19 Jul 2022, 05:16
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Re: $3000 is distributed among A, B and C such that A gets 2 3 rd of w [#permalink]
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