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3x^2 + 2x - 8 =

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Joined: 05 May 2012
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3x^2 + 2x - 8 = [#permalink]

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New post 13 May 2012, 22:53
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

75% (02:02) correct 25% (01:06) wrong based on 218 sessions

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3x^2 + 2x - 8 =

A. (3x-4)(x-2)
B. (3x-4)(x+2)
C. (3x-4)(x-2)
D. (3x-2)(x+4)
E. none of above
[Reveal] Spoiler: OA
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Re: 3x^2 + 2x - 8 = [#permalink]

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New post 13 May 2012, 23:15
3x^2 + 2x - 8
= 3x^2 + 6x - 4x - 8
= 3x (x + 2) - 4 (x+2)
= (3x-4) (x+2)

Option B
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Re: 3x^2 + 2x - 8 = [#permalink]

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New post 14 May 2012, 00:09
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Re: 3x^2 + 2x - 8 = [#permalink]

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New post 14 May 2012, 01:05
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3x^2 + 2x - 8

X1*X2=-8/3
X1+X2=-2/3

Only option B satisfies these parameters
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Re: 3x^2 + 2x - 8 = [#permalink]

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New post 05 Jul 2015, 03:49
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3x^2 + 2x - 8 = [#permalink]

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New post 21 Jan 2016, 07:11
1. just open the brackets. A is out, B is in. 30 secs.

2. factoring box

a. 3x^2 + 2x - 8 -> mulptiply a and c = 3*-8 = -24
b. factors of -24 that add up to b (i.e. 2) are 6 and -4 (note that the larger factor should be positive because b is positive, one of the factors is negative)
c. arrange the box as below and find common factors in the 2 vertical and 2 horizontal lines. form equation. of (3x-4)(x+2)
Attachments

box.jpg
box.jpg [ 7.22 KiB | Viewed 1902 times ]


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3x^2 + 2x - 8 =   [#permalink] 21 Jan 2016, 07:11
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