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saswata4s
4 Bells toll together at 9:00 A.M. They toll after 7, 8, 11 and 12 seconds respectively. How many times will they toll together again in the next 3 hours?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7

This is not a sub-600 level question I'm afraid. To find the LCM of 7, 8, 11, and 12 makes this question roughly an 800 level question. Easy processing but finding the LCM for these 4 numbers is immensely difficult. Reminder: think before you post question difficulty and follow the guidelines
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Another approach to solve this
The LCM of 7, 8, 11 and 12 seconds is 1848 seconds

Therefore 1848/60 = 30.80

180/30.80 is obviously lower than 6 since 180/30 = 6

Therefore, the answer is C
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saswata4s
4 Bells toll together at 9:00 A.M. They toll after 7, 8, 11 and 12 seconds respectively. How many times will they toll together again in the next 3 hours?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7

They will toll again after every LCM (7,8,11,12) = 1848 second

no. of times the bell will ring in 3 hrs = 10800 seconds = 10800/1848 = 5.8 or 5 times
adding the first time we get the total no as 6 times.
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In order to find the time taken by 4 bells to toll together again after 9 AM, we need to find LCM of (7,8,11,12) secs.

Time taken = LCM of (7,8,11,12) =7*11*24 secs =(7*11*24)/60 minutes = (7*11*2)/5 = 154/5 = 30.8 mins

That means, After 9 AM , all 4 bells will toll together after every 30.8 mins .

Number of times , the bells will toll together again in the next 3 hours = (3*60)/30.8

Since the answer should be an integer, we can approximate it as an integer less than 6 i.e 5

Option C is the answer.

Thanks,
Clifin J Francis
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How does one find the LCM of these four numbers?
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How did you guys figure out that the LCM needs to be taken out here? Like when I read the question, this did not cross my mind. How do i improve this ?
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Hi inciduntveniam,

Great question, because this is exactly the kind of recognition that comes from spotting a pattern type, not from the numbers themselves.

Look at what the posted solutions (Kurtosis, Abhishek) jumped to: LCM. Here's the reasoning they skipped over.

Why LCM is the tool

Think about one bell at a time. The bell with a 7-second period tolls at 7, 14, 21, 28 ... seconds - i.e. at every multiple of 7. The 8-second bell tolls at every multiple of 8. And so on.

Now ask: at what moment do all four toll at once again? It has to be a time that is simultaneously a multiple of 7, of 8, of 11, and of 12 - in other words, a common multiple of all four periods.

There are infinitely many common multiples, but the first time they re-coincide is the smallest one. "Smallest common multiple of several numbers" is literally the definition of LCM. That's the whole link.

The trigger to memorize

Whenever several things repeat on their own fixed cycles and you're asked when they next line up together, that's an LCM situation - bells tolling, lights blinking, runners meeting at a start line, gears returning to position. (The mirror-image cue - "largest size that divides several quantities evenly" - points to GCD instead.)

Lock it in with a tiny version

Forget the ugly numbers. Suppose two bells toll every 2 and 3 seconds:
- 2-bell: 2, 4, 6, 8, 10, 12 ...
- 3-bell: 3, 6, 9, 12 ...

List them by hand and you'll see them first meet at 6 seconds - which is exactly LCM(2, 3). Once you feel why 6 is the answer here, the 1848 in the original is the same idea, just with bigger numbers.

So the skill to build isn't computing LCM - it's recognizing "independent cycles, when do they coincide?" - LCM.

Answer: C

inciduntveniam
How did you guys figure out that the LCM needs to be taken out here? Like when I read the question, this did not cross my mind. How do i improve this ?
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Thankyou so much, understood :)
egmat
Hi inciduntveniam,

Great question, because this is exactly the kind of recognition that comes from spotting a pattern type, not from the numbers themselves.

Look at what the posted solutions (Kurtosis, Abhishek) jumped to: LCM. Here's the reasoning they skipped over.

Why LCM is the tool

Think about one bell at a time. The bell with a 7-second period tolls at 7, 14, 21, 28 ... seconds - i.e. at every multiple of 7. The 8-second bell tolls at every multiple of 8. And so on.

Now ask: at what moment do all four toll at once again? It has to be a time that is simultaneously a multiple of 7, of 8, of 11, and of 12 - in other words, a common multiple of all four periods.

There are infinitely many common multiples, but the first time they re-coincide is the smallest one. "Smallest common multiple of several numbers" is literally the definition of LCM. That's the whole link.

The trigger to memorize

Whenever several things repeat on their own fixed cycles and you're asked when they next line up together, that's an LCM situation - bells tolling, lights blinking, runners meeting at a start line, gears returning to position. (The mirror-image cue - "largest size that divides several quantities evenly" - points to GCD instead.)

Lock it in with a tiny version

Forget the ugly numbers. Suppose two bells toll every 2 and 3 seconds:
- 2-bell: 2, 4, 6, 8, 10, 12 ...
- 3-bell: 3, 6, 9, 12 ...

List them by hand and you'll see them first meet at 6 seconds - which is exactly LCM(2, 3). Once you feel why 6 is the answer here, the 1848 in the original is the same idea, just with bigger numbers.

So the skill to build isn't computing LCM - it's recognizing "independent cycles, when do they coincide?" - LCM.

Answer: C


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