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(429)^2 * 237 * (1243)^3 is thrice of ?

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(429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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(429)^2 * 237 * (1243)^3 is thrice of ?

A. 33605 * 31960 * (1243)^2
B. 33654 * 538219 * (1243)^2
C. 33891 * 533247 * (1243)^2
D. 34122 * 532004 * (1243)^2
E. 34606 * 534572 * (1243)^2
[Reveal] Spoiler: OA

Last edited by Bunuel on 02 Aug 2012, 04:25, edited 2 times in total.
Edited the question and added the OA

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Re: Number System [#permalink]

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surendar26 wrote:
(429)^2 * 237 * (1243)^3 is thrice of ?

33605 * 31960 * (1243)^2
33654 * 538219 * (1243)^2
33891 * 533247 * (1243)^2
34122 * 532004 * (1243)^2
34606 * 534572 * (1243)^2


(429)^2*237*(1243)^3 is an odd number.

Among answer choices only C is an odd number, (so thrice C also will be an odd number).

Answer: C.
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Re: Number System [#permalink]

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New post 14 Jan 2011, 17:49
Bunuel wrote:
surendar26 wrote:
(429)^2 * 237 * (1243)^3 is thrice of ?

33605 * 31960 * (1243)^2
33654 * 538219 * (1243)^2
33891 * 533247 * (1243)^2
34122 * 532004 * (1243)^2
34606 * 534572 * (1243)^2


(429)^2*237*(1243)^3 is an odd number.

Among answer choices only C is an odd number, (so thrice C also will be an odd number).

Answer: C.



Wow !!! the best approach.... toooo good...
+1 kudos...

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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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New post 03 Jul 2012, 14:22
Is there a factor rule or something which allows it to be possible to solve this by taking the numbers digit of 429^2 and see that it will be 1 which suits only answer choice C ?

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Re: Number System [#permalink]

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New post 02 May 2013, 11:15
Bunuel wrote:
surendar26 wrote:
(429)^2 * 237 * (1243)^3 is thrice of ?

33605 * 31960 * (1243)^2
33654 * 538219 * (1243)^2
33891 * 533247 * (1243)^2
34122 * 532004 * (1243)^2
34606 * 534572 * (1243)^2


(429)^2*237*(1243)^3 is an odd number.

Among answer choices only C is an odd number, (so thrice C also will be an odd number).

Answer: C.



If I were to approach the problem in this way...

429^2 * 237 * 1243 * 3 * 1243^2 must be equal to one of the choices...hence 429^2 * 237 * 1243 * 3 must be equal to the part after cancelling^2.
Considering the multiplication and its unit place...the value unit place 429^2 * 237 * 1243 * 3 must be 3. None of the choices seem to satisfy that.

Unit place Choice 1 : 0 Choice 2: 6 Choice 3: 7 Choice 4: 8 and Choice 5: 2....So if I were to guess, none of them might be the answer :)

Am I doing something wrong? Please correct me if either my process or values are off :)

Thanks!
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Re: Number System [#permalink]

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New post 02 May 2013, 11:59
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arpanpatnaik wrote:
Bunuel wrote:
surendar26 wrote:
(429)^2 * 237 * (1243)^3 is thrice of ?

33605 * 31960 * (1243)^2
33654 * 538219 * (1243)^2
33891 * 533247 * (1243)^2
34122 * 532004 * (1243)^2
34606 * 534572 * (1243)^2


(429)^2*237*(1243)^3 is an odd number.

Among answer choices only C is an odd number, (so thrice C also will be an odd number).

Answer: C.



If I were to approach the problem in this way...

429^2 * 237 * 1243 * 3 * 1243^2 must be equal to one of the choices...hence 429^2 * 237 * 1243 * 3 must be equal to the part after cancelling^2.
Considering the multiplication and its unit place...the value unit place 429^2 * 237 * 1243 * 3 must be 3. None of the choices seem to satisfy that.

Unit place Choice 1 : 0 Choice 2: 6 Choice 3: 7 Choice 4: 8 and Choice 5: 2....So if I were to guess, none of them might be the answer :)

Am I doing something wrong? Please correct me if either my process or values are off :)

Thanks!


\((429)^2\) * 237 * \((1243)^3\)
So we have \((429)^2\) * 237 * \((1243)\) * \((1243)^2\)
the units digit, will be 9^2 = 81 , 237 , 1243 and \((3)^2\) = 9
units digit will be, 1 * 7 * 3 * 9 = 189

Now test the units digit of the answer choices
As \((429)^2\) * 237 * \((1243)^3\) = 3 times of (X),
we are looking for an answer choice that gives the unit digit of 3.


33605 * 31960 * (1243)^2 = 5 * 0 * 9 = 0 (ruled out)
33654 * 538219 * (1243)^2 = 4 * 9 * 9 = 324 (ruled out)
33891 * 533247 * (1243)^2 = 1 * 7 * 9 = 63 ---> thats our answer
34122 * 532004 * (1243)^2 = 2 * 4 * 9 = 72 (ruled out)
34606 * 534572 * (1243)^2 = 6 * 2 * 9 = 108 (ruled out)
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Re: Number System [#permalink]

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New post 02 May 2013, 12:03
arpanpatnaik wrote:


If I were to approach the problem in this way...

429^2 * 237 * 1243 * 3 * 1243^2 must be equal to one of the choices...hence 429^2 * 237 * 1243 * 3 must be equal to the part after cancelling^2.
Considering the multiplication and its unit place...the value unit place 429^2 * 237 * 1243 * 3 must be 3. None of the choices seem to satisfy that.

Unit place Choice 1 : 0 Choice 2: 6 Choice 3: 7 Choice 4: 8 and Choice 5: 2....So if I were to guess, none of them might be the answer :)

Am I doing something wrong? Please correct me if either my process or values are off :)

Thanks!


the mistake you did was multiplying (429^2 * 237 * 1243^3) by 3, when the question states
(429^2 * 237 * 1243^3) = 3 times of (answer)
which is, (429^2 * 237 * 1243^3) / 3 = (answer)
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Re: Number System [#permalink]

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New post 02 May 2013, 12:08
karishmatandon wrote:
arpanpatnaik wrote:


If I were to approach the problem in this way...

429^2 * 237 * 1243 * 3 * 1243^2 must be equal to one of the choices...hence 429^2 * 237 * 1243 * 3 must be equal to the part after cancelling^2.
Considering the multiplication and its unit place...the value unit place 429^2 * 237 * 1243 * 3 must be 3. None of the choices seem to satisfy that.

Unit place Choice 1 : 0 Choice 2: 6 Choice 3: 7 Choice 4: 8 and Choice 5: 2....So if I were to guess, none of them might be the answer :)

Am I doing something wrong? Please correct me if either my process or values are off :)

Thanks!


the mistake you did was multiplying (429^2 * 237 * 1243^3) by 3, when the question states
(429^2 * 237 * 1243^3) = 3 times of (answer)
which is, (429^2 * 237 * 1243^3) / 3 = (answer)


Ahh! Didnt read the question properly :) Sorryy!! :) and thanks for the help Karishma! :)
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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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New post 16 Sep 2013, 00:23
Square of 429: As the last digit is "9", its square should give "1" at the end.
Only option C best fits in, so answer = C
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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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New post 17 Jan 2014, 04:51
somalwar wrote:
Square of 429: As the last digit is "9", its square should give "1" at the end.
Only option C best fits in, so answer = C


did it just like you. quite risky but took 30 seconds :D

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Re: Number System [#permalink]

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New post 17 Jan 2014, 05:13
Bunuel wrote:
surendar26 wrote:
(429)^2 * 237 * (1243)^3 is thrice of ?

33605 * 31960 * (1243)^2
33654 * 538219 * (1243)^2
33891 * 533247 * (1243)^2
34122 * 532004 * (1243)^2
34606 * 534572 * (1243)^2


(429)^2*237*(1243)^3 is an odd number.

Among answer choices only C is an odd number, (so thrice C also will be an odd number).

Answer: C.


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Once again Bunuel sama...why r u so awesome

We need to have tab for +10 kudos as well

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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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New post 26 Feb 2014, 19:04
unceldolan wrote:
somalwar wrote:
Square of 429: As the last digit is "9", its square should give "1" at the end.
Only option C best fits in, so answer = C


did it just like you. quite risky but took 30 seconds :D


One more check, divide 237 by 3 comes up 79

79 x 1237 = Last digit is 3, so option C works fine

Answer = C
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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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Re: (429)^2 * 237 * (1243)^3 is thrice of ? [#permalink]

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Re: (429)^2 * 237 * (1243)^3 is thrice of ?   [#permalink] 06 Aug 2017, 12:07
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