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E-5=3(A-5) i.e. E-5 =3A-15
E+3=2(A+3) i.e. E+3=2A+ 6

On Solving , A=13 and E=29 , so E+A=42
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(e-5) = 3(a-5) - (1)
(e+3) = 2(a+3) - (2)

e+a?

(1) - (2)

-8 = a - 21
a = 13
e = 29

Sum = 42

IMO: E
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Let Ebu's current age be E, and Atu's current age be A.

From the problem statement, we have two conditions:

1. Five years ago, Ebu was three times as old as Atu:
E - 5 = 3(A - 5)

2. In three years, Ebu will be twice as old as Atu:
E + 3 = 2(A + 3)

We can solve these equations step by step.

Step 1: Simplify the first equation*l

E - 5 = 3(A - 5)
E - 5 = 3A - 15
E = 3A - 10 ...(i)

Step 2: Simplify the second equation

E + 3 = 2(A + 3)
E + 3 = 2A + 6
E = 2A + 3 ...(ii)

Step 3: Equate equations (i) and (ii)

3A - 10 = 2A + 3
3A - 2A = 3 + 10
A = 13

Step 4: Substitute A = 13 into equation (ii) to find E**

E = 2A + 3
E = 2(13) + 3
E = 26 + 3
E = 29

Therefore, Ebu is 29 years old, and Atu is 13 years old.

The sum of their current ages is:
E + A = 29 + 13 = 42

Thus, the correct answer is 42.

Answer: E. 42
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E-5=3(A-5)
E-5 =3A-15
E+3=2(A+3)
E+3=2A+ 6
A=13 and E=29
E+A=42
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