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6*6*6 = 216
3*3*3 = 27
216+27 = 243

factors of 243
3*81 = 243
3*27 = 81
3* 9 = 27
3* 3 = 9

3^5 Answer A
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\(6^3 + 3^3 = 3^3(1+2^3) = 3^3×9 = 3^5\)

IMO A

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Sajjad1994
\(6^3 + 3^3 =\)

(A) \(3^5\)

(B) \(3^9\)

(C) \(2(3^3)\)

(D) \(3^6\)

(E) \(3^7\)

\(6^3 + 3^3 =(2^3)*(3^3)+3^3=8*3^3+3^3=9*3^3=(3^2)*(3^3)=3^5\) A)
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Sajjad1994
\(6^3 + 3^3 =\)

(A) \(3^5\)

(B) \(3^9\)

(C) \(2(3^3)\)

(D) \(3^6\)

(E) \(3^7\)
Solution:

Simplifying, we have:

(2 x 3)^3 + 3^3

2^3 x 3^3 + 3^3

3^3 x (2^3 + 1)

3^3 x 9

3^5

Answer: A
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\(6^3 + 3^3: (2 * 3)^3 + 3^3\)

=> \(2^3 . 3^3 + 3^3\)

=> \(3^3 (2^3 + 1)\)

=> \(3^3 (9)\)

=> \(3^3 (3^2)\)

=> \(3^5\)

Answer A
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