Bunuel
65% of women with a bifid uterus, a uterus which is divided into two lateral horns as a result of imperfect fusion of the paramesonephric ducts, give birth prematurely. However, 95% of prematurely born infants are born to mothers whose uterus is not bifid.
The statements above, if true, best support which of the following as a conclusion?
(A) 15% of women with a bifid uterus end up losing the fetus.
(B) Some causes of premature birth reside in factors other than the physiology of the birth mother
(C) A bifid uterus is not necessarily hereditary.
(D) The birth weight of premature infants whose mothers have a bifid uterus is lower than that of premature infants whose mothers do not have a bifid uterus.
(E) A bifid uterus is an uncommon condition among women.
Premise: 65% women with a certain medical condition give birth prematurely
Evidence: 95% of women who give birth prematurely do not have the above condition
Question type: Conclusion
Analysis: Total premature births = 100
...95% are without condition = 95
...that is 5% are with condition = 5
...these 5 represent 65% of premature births to women with certain condition
Conclusion: Rare cases, very few in numberWe need to find an answer which gives us a rare case response.
A. This option gives us consequence of 65% women.
15% doesn't make sense as 100-65 = 35% without premature births or death, seems arbitrary to allocate 15% to deaths without knowing normal birth share. Incorrect.
B.
Some and other causes of premature birth are not sequential statement that can follow Premise and evidence given. Incorrect.
C.
What kind of condition is given. This is not relevant. Incorrect.
D.
Weight of babies from two different categories is given. This cannot be the sequential statement that can follow Premise and evidence given. Incorrect.
E.
Uncommon condition refers to rare cases. So this is indeed the correct answer.
Therefore, option E is the correct answer.
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