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15 Nov 2019, 01:42
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E
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Difficulty:
45%
(medium)
Question Stats:
71% (02:15) correct
29%
(02:05)
wrong
based on 389
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{a^4 + 1}{a^2}\) =
A. \((a+\frac{1}{a})(a-\frac{1}{a})\)
B. \((a+\frac{1}{a})^2\)
C. \((a + \frac{\sqrt{2}}{a})(a - \frac{\sqrt{2}}{a})\)
D. \((a + \sqrt{2} + \frac{1}{a})(a - \sqrt{2} - \frac{1}{a})\)
E. \((a + \sqrt{2} + \frac{1}{a})(a - \sqrt{2} + \frac{1}{a})\)
Are You Up For the Challenge: 700 Level Questions
A. \((a+\frac{1}{a})(a-\frac{1}{a})\)
B. \((a+\frac{1}{a})^2\)
C. \((a + \frac{\sqrt{2}}{a})(a - \frac{\sqrt{2}}{a})\)
D. \((a + \sqrt{2} + \frac{1}{a})(a - \sqrt{2} - \frac{1}{a})\)
E. \((a + \sqrt{2} + \frac{1}{a})(a - \sqrt{2} + \frac{1}{a})\)
Are You Up For the Challenge: 700 Level Questions
15 Nov 2019, 01:52
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Bunuel
\(\frac{a^4 + 1}{a^2}\)
--> \(a^2 + \frac{1}{a^2}\)
--> \(a^2 + \frac{1}{a^2} + 2*a*\frac{1}{a} - 2*a*\frac{1}{a}\)
--> \((a + \frac{1}{a})^2 - 2\)
--> \((a + \frac{1}{a})^2 - (\sqrt{2})^2\)
--> \((a + \frac{1}{a} + \sqrt{2})(a + \frac{1}{a} - \sqrt{2})\)
IMO Option E
