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Bunuel
A 6-sided cube has sides numbered 1 through 6. If the cube is rolled twice, what is the probability that the sum of the two rolls is equal to 8?

(A) 1/9
(B) 1/8
(C) 5/36
(D) 1/6
(E) 7/36


for sum to come 8 we have
(2,6),(3,5),(4,4),(5,3),(6,2)

5 possiblities and total 36

5/36 IMO C
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Bunuel
A 6-sided cube has sides numbered 1 through 6. If the cube is rolled twice, what is the probability that the sum of the two rolls is equal to 8?

(A) 1/9
(B) 1/8
(C) 5/36
(D) 1/6
(E) 7/36

Solution:

There are 6 x 6 = 36 outcomes when the cube is rolled twice. The outcomes that yield a sum of 8 are: {2, 6}, {3, 5}, {4,4}, {5, 3} and {6, 2}. Therefore, the probability is 5/36.

Answer: C
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Given that A 6-sided cube has sides numbered 1 through 6 and We need to find If the cube is rolled twice, what is the probability that the sum of the two rolls is equal to 8?

As we are rolling the cube twice => Number of cases = \(6^2\) = 36

Out of the 38 cases let's find out the cases in which we can get the sum 8. The cases are as follows:
(2,6), (3,5), (4,4), (5,3), (6,2)
=> 5 cases

=> probability that the sum of the two rolls is equal to 8 = \(\frac{5}{36}\)

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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