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Updated on: 22 Jul 2019, 05:35
Originally posted by Bunuel on 09 Oct 2018, 23:33.
Last edited by Sajjad1994 on 22 Jul 2019, 05:35, edited 1 time in total.
Last edited by Sajjad1994 on 22 Jul 2019, 05:35, edited 1 time in total.
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B
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Difficulty:
5%
(low)
Question Stats:
89% (00:48) correct
11%
(00:42)
wrong
based on 53
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A and B are centers of two circles that touch each other externally, as shown in the figure. What is the area of the circle whose diameter is AB ?
(A) \(4\pi\)
(B) \(\frac{25\pi}{4}\)
(C) \(9\pi\)
(D) \(16\pi\)
(E) \(25\pi\)
Source: Nova GMAT
Difficulty Level: 550
Difficulty Level: 550
Attachment:
circles.jpg [ 26.87 KiB | Viewed 3238 times ]
10 Oct 2018, 01:24
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Bunuel
From the figure it may be inferred that AB = 5
i.e. Diameter of Circle = 5
i.e. Radius = 5/2
\(Area = πr^2 = π(5/2)^2 = (25/4)π\)
Answer: Option B
10 Oct 2018, 01:41
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As shown in the attachment:
Diameter of red circle is \(D=2+3=5\)
so radius is \(r=\frac{5}{2}\)
Area of circle is \(A=πr^2\)
\(A=π*(\frac{5}{2})^2\)
\(A= \frac{25π}{4}\)
Diameter of red circle is \(D=2+3=5\)
so radius is \(r=\frac{5}{2}\)
Area of circle is \(A=πr^2\)
\(A=π*(\frac{5}{2})^2\)
\(A= \frac{25π}{4}\)
Attachments
Capture.PNG [ 29.18 KiB | Viewed 2948 times ]
