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1/A + 1/B = 1/72 ----- (i)
1/B + 1/C = 1/120 ---- (ii)
Subtracting (i) and (ii)
1/A - 1/C = 1/180 ---- (iii)
1/A + 1/C = 1/90 ---- (iv)
Adding (iii) and (iv)
2/A = (1+2)/180 = 3/180 = 1/60
2/A = 1/60
1/A = 120
A = 120
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Ans B

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Can you please explain how are we calculating efficiency?

The efficiency of an individual? It is mentioned to the right in the pic. Firstly, we are calculating the combined efficiency, then we are substituting the eff. of an individual.

Geet03

Let me share another pic with complete detail and please tag me for any further clarification

Posted from my mobile device
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