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a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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15 Apr 2016, 07:09
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a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]? A. 524 B. 693 C. 731 D. 970 E. None of the above
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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15 Apr 2016, 07:31
anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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15 Apr 2016, 07:27
Is the answer bank correct? Shouldn't option C be 713?
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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06 Aug 2018, 22:26
chetan2u wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C Hi chetan2u, This might be a really stupid question but why could you please help understand why we didn't we take the value of abc as 987 which would make \([abc – (a+b+c)]\) = \(987  (9+8+7)\) = 963 ?



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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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06 Aug 2018, 22:36
Shruti0805 wrote: chetan2u wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C Hi chetan2u, This might be a really stupid question but why could you please help understand why we didn't we take the value of abc as 987 which would make \([abc – (a+b+c)]\) = \(987  (9+8+7)\) = 963 ? Shruti, Reason is abc is a*b*c so 9*8*7=504 But you are taking it as 987 a 3digit number. If a and B are negative, ABC cannot be a integer.
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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04 Sep 2018, 05:52
chetan2u wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C to get the maximum value, we should have the maximum value of abc = (10)(10)(9) = 900 plus the maximum value of (a+b+c) =  (10  9  8) = (27) = +27 so, the maxmium value should be 900+27 = 927 please kindly help advise if there's any problem with my concept here? Thanks



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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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04 Sep 2018, 05:57
Monnie wrote: chetan2u wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C to get the maximum value, we should have the maximum value of abc = (10)(10)(9) = 900 plus the maximum value of (a+b+c) =  (10  9  8) = (27) = +27 so, the maxmium value should be 900+27 = 927 please kindly help advise if there's any problem with my concept here? Thanks Ok, I got my problem!



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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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04 Sep 2018, 05:58
Monnie wrote: [to get the maximum value, we should have the maximum value of abc = (10)(10)(9) = 900 plus the maximum value of (a+b+c) =  (10  9  8) = (27) = +27 so, the maxmium value should be 900+27 = 927
please kindly help advise if there's any problem with my concept here? Thanks The prompt indicates that a ≠ b ≠ c, so a=10 and b=10 is not a viable case.
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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04 Sep 2018, 05:59
Monnie wrote: chetan2u wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Hi, since we are looking for the maximum possible value, we will take two smallest negative integer, 10 and 9, and the largest possible positive integer thereafter.. few points 1) we are taking two ive and one +, so that the PRODUCT can be +.. 2) we are taking biggest NUMERIC value in , as a+b+c will become largest possible  integer, which will become + after being multiplied by another  signso \([abc – (a+b+c)] = (10)(9)(8)  (109+8) = 720(11) = 731\) C to get the maximum value, we should have the maximum value of abc = (10)(10)(9) = 900 plus the maximum value of (a+b+c) =  (10  9  8) = (27) = +27 so, the maxmium value should be 900+27 = 927 please kindly help advise if there's any problem with my concept here? Thanks abc and a+b+c are part of same equation so you have take same value of a,B and c in both abc and a+b+c.. but here you have taken 10,10,9 and 10,9,8 Secondly when you have taken abc you have taken a as 10 and b as 10 but it is given a is not equal to b but you have taken both 10=10 hence wrong
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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11 Sep 2018, 22:29
anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Can't we take the value of 'a' greater than 10? e.g., a=20, 100,..



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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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11 Sep 2018, 22:37
castiel wrote: anceer wrote: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What will be the maximum possible value of [abc – (a+b+c)]?
A. 524 B. 693 C. 731 D. 970 E. None of the above Can't we take the value of 'a' greater than 10? e.g., a=20, 100,.. no because it is given that 10 ≤ a, b, c ≤ 10, so a has to be within 10 and 10, that is any of 10,9,8,7,6,5.....0,1,2,3....8,9,10
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil
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11 Sep 2018, 22:43
We can take 10,9 and 8 to make the quantity max. Also abc>0 and (a+b+c)<0 a=10,b=9 and c=8 C) will be the answer.




Re: a, b, c are integers. a ≠ b ≠ c and 10 ≤ a, b, c ≤ 10. What wil &nbs
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