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A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is pick

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A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is pick  [#permalink]

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New post Updated on: 09 Apr 2018, 01:21
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A
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C
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Question Stats:

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A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is picked at random, what is the probability that the ball drawn will be either a red or a black ball?


a. 7/19
b. 9/19
c. 10/19
d. 11/19
e. 12/19


Source- time4education

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Originally posted by Nixondutta on 08 Apr 2018, 23:56.
Last edited by Bunuel on 09 Apr 2018, 01:21, edited 1 time in total.
Edited the question.
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Re: A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is pick  [#permalink]

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New post 09 Apr 2018, 00:27
Nixondutta wrote:
A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is picked at random, what is the probability that the ball drawn will be either a red or a black ball?
Source- time4education


a.7/19
b.9/19
c.10/19
d.11/19
e.12/19


probablity=\(\frac{(7C1+3C1)}{(19C1)}\)

option C
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Re: A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is pick  [#permalink]

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New post 04 Jun 2018, 13:55
P(AorB) = P(A)+P(B)-P(A and B)

total balls =19
probablity of chooisng a red ball = 7/19 = P(A)
probablity of choosing a black ball = 3/19 = P(B)
probability of choosing a black and red ball = 0 (not possible as it either be red or black)

P(A or B) = 7/19 + 3/19 -0 = 10/19

so C



Nixondutta wrote:
A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is picked at random, what is the probability that the ball drawn will be either a red or a black ball?


a. 7/19
b. 9/19
c. 10/19
d. 11/19
e. 12/19


Source- time4education
Re: A bag contains 7 red, 9 yellow, and 3 black balls. If a ball is pick &nbs [#permalink] 04 Jun 2018, 13:55
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